Given:
AB is the diameter of a circle.
m∠CAB = 26°
To find:
The measure of m∠CBA.
Solution:
Angle formed in the diameter of a circle is always 90°.
⇒ m∠ACB = 90°
In triangle ACB,
Sum of the angles in the triangle = 180°
m∠CAB + m∠ACB + m∠CBA = 180°
26° + 90° + m∠CBA = 180°
116° + m∠CBA = 180°
Subtract 116° from both sides.
116° + m∠CBA - 116° = 180° - 116°
m∠CBA = 64°
The measure of m∠CBA is 64°.
Answer:
Step-by-step explanation:
Notice when x increases 1, y is 4 times the previous one, so
the function is like 
To determine the constant C, put any pair of (x, y)
Use x = 0, y = 0.2, so
0.2 = 
= C * 1 = C
then
- 1/3 - 1 2/3 = - 2
When subtracting two negatives you add the two numbers together.
Answer:
16
Step-by-step explanation:
Let's give letters as the image. Triangle ABH is a right triangle, so you can apply pythagoream theorem. In particular, it's the classic "3-4-5" triangle (there are some triplets of integers that gives you a right triangle, and 3-4-5 is the most famous). Either way, the height of the triangle is 4.
At that point you can compute the area by multiplying base and height, and the total surface is 16.
Answer:
isosceles triangle
Step-by-step explanation:
line CB is the transversal for the two parallel lines, so angle CBA and angle BCE are the same.
since a straight line is 180 degrees, we can solve for angle BCA by subtracting the other angles on the line from 180
180-80-50 = 50
since triangles have 180 degrees, we can solve for the last angle by subtracting the angles we already know from 180
180-80-50
two of the angles are the same, making this an isosceles triangle
