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lord [1]
4 years ago
14

A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4 °F. The submarine div

es down 115 feet deeper, and the water temperature drops by 2 1/5 °F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation.
Write an expression to represent the submarine’s elevation after its final dive. Then simplify the expression to find its elevation.
Mathematics
2 answers:
aleksley [76]4 years ago
7 0

Answer:

-502.5 - 115 = - 617.5

63 1/4 - 2 1/5 =  

63 - 2 = 61

1/4 - 1/5 = 5/20 - 4/20 = 1/20

so 63 1/4 - 2 1/5 = 61 1/20

after the sub dove, elevation level is - 617.5 and temp is 61 1/20 F

Step-by-step explanation:

dlinn [17]4 years ago
3 0
I just nendhdjsisiaidudj but the guy is correct
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Find p and q for which the linear eqn has infinite solutions 6x-(2p-3)y-2q-3=0, 12x-( 2p-1)y-5q+1=0
astra-53 [7]

Answer:

p= 2.5

q= 7

Step-by-step explanation:

The lines should overlap to have infinite solutions, slopes should be same and y-intercepts should be same.

Equations in slope- intercept form:

  • 6x-(2p-3)y-2q-3=0 ⇒ (2p-3)y= 6x -2q-3 ⇒ y= 6/(2p-3)x -(2q+3)/(2p-3)
  • 12x-( 2p-1)y-5q+1=0 ⇒ (2p-1)y= 12x - 5q+1 ⇒  y=12/(2p-1)x - (5q-1)/(2p-1)

<u>Slopes equal:</u>

6/(2p-3)= 12/(2p-1)

6(2p-1)= 12(2p-3)

12p- 6= 24p - 36

12p= 30

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(2q+3)/(2p-3)= (5q-1)/(2p-1)

(2q+3)/(2*2.5-3)= (5q-1)/(2*2.5-1)

(2q+3)/2= (5q-1)/4

4(2q+3)= 2(5q-1)

8q+12= 10q- 2

2q= 14

q= 7

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