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4 years ago

Find the volume. Thank you!!!

Mathematics

2 answers:

Alex Ar [27]4 years ago

7 0

Answer:

Step-by-step explanation:

7*2*8

L*W*H

Montano1993 [528]4 years ago

4 0

Answer is 42
- Base * height
- Base = 7*2*.5
- Height = 6

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How would I find x?

lidiya [134]

Answer:

f(x) = y

Step-by-step explanation:

f(x) always equals y, so the equation would be y = 7. therefore, I am pretty sure that x = y, but you may want to wait to ask your teacher. If there is more detail, message me!

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3 years ago

A group of 8 friends went to lunch and spent a total of $76, which included the food bill and a tip of $16. they decided to spli

Savatey [412]

Answer:

A, c(excluding tip, if the tip is included then c is not the answer)

Step-by-step explanation:

I solved the Equations:

A)1/8(x+16)=76/8----60 (this is the correct answer!)

B)1/8(x+16=76)------ 592 (NOT the correct answer

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4 years ago

Help answer please! math question

sweet-ann [11.9K]

Answer:

he will use 2 posts.

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= $84\times15=1260$