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goblinko [34]
3 years ago
13

jocelyn bought 2 sweaters for the same price. she paid 23.56,including sales tax of 1.36 and a 5.00 discount coupon. what was th

e price of 1 sweater before the tax and coupon.
Mathematics
1 answer:
wel3 years ago
6 0
Number of sweaters bought by Jocelyn = 2
Price of the 2 sweaters including tax and discount coupon = 23.56
Amount of ales tax taken = 1.36
Amount of discount coupon = 5.00
Then
Price of 2 sweaters before tax = 23.56 - 1.36
                                                 = 22.20
Then
Price of the sweater before discount coupon was applied = 22.20 + 5.00
                                                                                             = 27.20
So
Price of 1 sweater before tax and coupon discount = 27.2/2
                                                                                   = 13.6
So the price of 1 sweater before tax and coupon discount is 13.6.
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{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

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{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

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{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Let, ABCD be the rhombus shaped field and each side of the field be x

[ All sides of the rhombus are equal, therefore we will let the each side of the field be x ]

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\longrightarrow  \tt AB+BC+CD+AD=400m

\longrightarrow  \tt x + x + x + x=400

\longrightarrow  \tt 4x=400

\longrightarrow  \tt  \: x =  \dfrac{400}{4}

\longrightarrow  \tt x= \red{100m}

\therefore Each side of the field = <u>100m</u><u>.</u>

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So, For \triangle ABD,

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\therefore \tt Simi \:  perimeter \:  [S] =  \boxed{ \sf \dfrac{a + b + c}{2} }

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\star \tt Area  \: of  \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star

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• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

<u>Putt</u><u>ing</u><u> the</u><u> values</u><u>,</u>

\longrightarrow \tt  Area_{ ( \triangle \:  ABD)} =  \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }

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Area of \triangle BCD = 4800 m²

<u>Therefore, area each of them [son and daughter] will get = 4800 m²</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

{\underline{\rule{290pt}{2pt}}}

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