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serg [7]
3 years ago
10

Jada walks to school. The function D givers her distance from school, in meters, t minutes since she left home. Which equation t

ells us “Jada is 600 meters from school after 5 minutes”? A. D(600)=5 B. t(5)=600 C. t(600)=5 D. D(5)=600
Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0

Answer:

t(5)=600.................

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A bakery used 38 pounds of flour to make French bread and
fomenos

Answer:

since we are not given the options, I will write down a few equations that represent the number of French bread loaves and bagels:

  • a = number of loaves of French bread
  • b = number of bagels
  • available amount of flour = 38

2a + b ≤ 38

2a ≤ 38 - b

a ≤ (38 - b) / 2

a ≤ 19 - 0.5b

b ≤ 38 - 2a

b ≤ 2(19 - a)

Hopefully one of these equations is one of the choices given to you.

8 0
2 years ago
Does anyone understand how to solve this?
Nataliya [291]

a f(a) is the function f(x) where x is replaced by a.

So we have

(3x^2 + x + 3 - (3a^2 + a + 3)) / ( x - a)

= (3x^2 - 3a^2 + x - a) / (x = a) Answer

b (3(x + h)^2 + x + h + 3 - (3x^2 + x + 3)) / h

= (3x^2 + 6xh + 3h^2 + x + h - 3x^2 - x - 3) ) / h

= (6xh + h + 3 h^2) / h

= 6x + 3h + 1 Answer



6 0
3 years ago
Solve the proportion<br> 4/k+3=8/14
MatroZZZ [7]
Cross multiply to get 8k+24=56 then solve for k so subtract 24 from each side to get 8k=32 so k=4
7 0
3 years ago
Read 2 more answers
Is it right
Rasek [7]
F(t) = t2 + 4t − 14

 

y + 14 + 4 = ( t2 + 4t +4)

y + 18 = ( t + 2)^2

 

so the vertex of the parabola is ( -2 , -18)

 

<span>the axis of symmetry is y = -18</span>

8 0
3 years ago
A 24-foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground 6 feet
andrezito [222]

Answer:

23.24 feet

Step-by-step explanation:

Use the pythagorean theorem: a² + b² = c², where a and b are legs of the right triangle and c is the hypotenuse.

In this situation, the ladder is the hypotenuse of the triangle, and the distance from the base of the building is the long leg.

Plug in the ladder length as c and plug in the distance from the base of the building as a:

a² + b² = c²

(6²) + b² = (24)²

36 + b² = 576

b² = 540

b = 23.24

So, the ladder reaches approximately 23.24 feet up the wall

5 0
2 years ago
Read 2 more answers
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