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Kamila [148]
3 years ago
8

Owen used these steps to solve the equation 4x+7=1+2(2x+3). Which choice describes the meaning of his result, 7=7?

Mathematics
1 answer:
ivanzaharov [21]3 years ago
6 0

Answer:

Option D. All values of x make the equation true

Step-by-step explanation:

<u><em>The options of the question are</em></u>

a.The result is not correct because Step 2 has an error.

b.The solution is x=7.

c.No values of x make the equation true.

d.All values of x make the equation true

we have the equation

4x+7=1+2(2x+3)

solve for x

Apply distributive property right side

4x+7=1+4x+6

Combine like terms

4x+7=4x+7

subtract 4x both sides

7=7

The equation has infinity solutions

.All values of x make the equation true

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Ramkin is going to flip a fair coin 100 times.
Gelneren [198K]

Answer:

50 times

Step-by-step explanation:

You are going to flip a coin 100 times. There are 2 sides. So, what you would do is divide 100 by two because there are two sides. There is a 50% chance that the coin will land on heads, and a 50% chance it will land on tails.

Please let me know if you have any more questions. Hope this helps!

3 0
3 years ago
Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.
Flauer [41]

Answer:

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

Step-by-step explanation:

Given

\sqrt{128a^{6}b^{13}}

Required

Solve

\sqrt{128a^{6}b^{13}}

The expression can be split to:

\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}

So, we have:

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}

Rewrite as:

\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2}  * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

5 0
3 years ago
Why does the value of money that you save increase over time
Marrrta [24]
The answer is A because it earns interest
8 0
3 years ago
Read 2 more answers
The approximate molar concentration of several chemicals are given. Find the pH of each use the calculator and round to the near
mojhsa [17]

Answer:

pH = 13 --- Oven Cleaner

pH = 6.2 --- Water

pH =7.4 --- Blood

pH = 2.2 --- Vinegar

Step-by-step explanation:

The given molar concentration are:[Missing from the question]

Oven Cleaner: [h+] = 10^{-13}

Water: [h+] = 0.0000007

Blood: [h+] = 0.00000004

Vinegar: [h+] = 0.0063

Required

Determine the pH

pH is calculated using:

pH = -\log(h+)

So, we have:

Oven Cleaner:

pH = -\log(10^{-13})

Using a calculator, we have:

pH = 13

Water:

pH = -\log(0.0000007)

Using a calculator, we have:

pH = -1*-6.2

pH = 6.2

Blood:

pH = -\log(0.00000004)

Using a calculator, we have:

pH = -1 * -7.4

pH =7.4

Vinegar:

pH = -\log(0.0063 )

Using a calculator, we have:

pH = -1 * -2.2

pH = 2.2

4 0
3 years ago
The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. The article "Testing P
zysi [14]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: breakdown voltage of an insulating liquid under certain conditions.

a)

Graphic in attachment.

Box: The median is closer to the third quartile than the first quartile showing skewness to the left.

The black dot in the middle of the box represents the sample mean (X[bar]) as you can see it is also moved to the right side of the distribution, affected by the presence of an outlier.

Whiskers:

The upper whisker is smaller than the lower one and there is a value that can be considered an outlier.

Altogether you can say that the distribution of the data set is skewed to the left.

b)

To estimate the population mean you need the population to be at least normal. The box plot shows that the distribution is not symmetrical but, considering that the sample size is n= 48 you can apply the Central Limit Theorem and approximate the sampling distribution to normal.

X[bar]≈N(μ;σ²)

As the distribution is approximate, using the sample standard deviation (since we don't know the population value) for the distribution standard deviation is also valid ⇒ Z= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

∑X= 2626 ∑X²= 144950 n= 48

X[bar]= ∑X/n= 2626/48= 54.71

S²= 1/n[∑X²- (∑X)²/n]= 1/47[144950-(2626)²/48]= 27.36

S= 5.23

Z_{1-\alpha /2}= Z_{0.975}= 1.96

54.71 ± 1.96 * \frac{5.23}{\sqrt{48} }

[53.22; 56.18]kV

c)

95% CI

amplitude a=2 kV  i.e. semi amplitude d= 1 kV

The semi amplitude or margin of error for the CI can be calculated as:

d= Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

From this formula you can clear the sample size

\frac{d}{Z_{1-\alpha /2}} = \frac{S}{\sqrt{n} }

(\frac{d}{Z_{1-\alpha /2}} )*\sqrt{n} = S

\sqrt{n} = S* (\frac{Z_{1-\alpha /2}}{d} )

n = (S* (\frac{Z_{1-\alpha /2}}{d} ))^2

n= (5.23*(\frac{1.96}{1} ))^2= 105.08= 106

3 0
3 years ago
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