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charle [14.2K]
4 years ago
8

HELP NOW PLEASE !!!Mrs. Havarti's art class made five identical conical sculptures. Each sculpture has a diameter of 9 cm and a

slant height of
16.5 cm. The lateral area of each sculpture is to be covered with newspaper. How many square centimeters of newspaper are
needed to cover the lateral areas of all five sculptures? (Use 3.14 for x and round to the nearest hundredth. Recall the formula
LA- rl.)
233.15 cm
466.29 cm
1,165.73 cm
2,331.45 cm
Mathematics
1 answer:
Zina [86]4 years ago
6 0

Answer:

1165.73 sq.cm. of newspaper are  needed to cover the lateral areas of all five sculptures

Step-by-step explanation:

Diameter of 1 sculpture = 9 cm

Radius of 1 sculpture =\frac{9}{2}=4.5 cm

Slant height of sculpture = l = 16.5 cm

Lateral surface area of each sculpture = \pi r l = \frac{22}{7} \times 4.5 \times 16.5 =233.3571 cm^2

Lateral surface area of 5 sculptures =233.3571 \times 5 =1165.73 cm^2

Hence 1165.73 sq.cm. of newspaper are  needed to cover the lateral areas of all five sculptures

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Answer:

a) The p-value obtained from the one-proportion applet is more valid because a z-test statistic shouldn't have been used for the other obtained p-value. Check Explanation for more Explanation.

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Step-by-step explanation:

The p-value for this problem was obtained from a one proportion simulation applet and another obtained using a one proportion z-test p-value.

But one of the conditions for the use of the z-test or the z-distribution in obtaining the p-value is that information on the population mean and standard deviation should be known or the sample size should be large enough such that the properties of the sample should approximate the properties of the the population distribution.

But for this question and hypothesis test, the sample that the we are working with is only of sample size 12 with no information on the population standard deviation provided, hence, the p-value obtained from the z-test statistic one proportion test is not a valid enough one due to this reason.

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Manual way of calculating

t = (x - μ)/σₓ

x = 5/12 = 0.41667

μ = p₀ = 0.20

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p-value (for t = 1.52, at 0.05 significance level, df = 11, with a one tailed condition) = 0.07836

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For this question, the null hypothesis is that there isn't enough evidence to suggest that a spun penny will land heads more that 20% of the time in the long run.

And the alternative hypothesis is that there is enough evidence to suggest that a spun penny will land heads more that 20% of the time in the long run.

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This means that we fail to reject the null hypothesis & say there isn't enough evidence to suggest that a spun penny will land heads more that 20% of the time in the long run.

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Therefore, the area that the dog can wander based on the information provided will be 931π.

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