I don't know the answer, but I suggest downloading the app: PhotoMath. It scans a math problem and shows you how to complete the problem. I hope this helped~!
That's correct but whats your question?
I think the answer is b i hope this helps
Answer:
r = 51.96 inches
Step-by-step explanation:
![V_{cone} = \pi {r}^{2} h \\ \\ \implies \: r^{2} = \frac{V_{cone}}{\pi h } \\ \\ \implies \: r^{2} = \frac{942}{3.14 {(9) } }\\ \\ \implies \: r^{2} = \frac{942}{3.14 {(9) } } \\ \\ \implies \: r^{2} =2700 \\ \\ \implies \: r= \sqrt{2700} \\ \\ \implies \: r=51.96 \: inches](https://tex.z-dn.net/?f=V_%7Bcone%7D%20%3D%20%5Cpi%20%7Br%7D%5E%7B2%7D%20h%20%20%5C%5C%20%20%5C%5C%20%20%5Cimplies%20%5C%3A%20r%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7BV_%7Bcone%7D%7D%7B%5Cpi%20h%20%7D%20%5C%5C%20%20%5C%5C%20%20%5Cimplies%20%5C%3A%20%20r%5E%7B2%7D%20%3D%20%20%5Cfrac%7B942%7D%7B3.14%20%7B%289%29%20%7D%20%7D%5C%5C%20%20%5C%5C%20%20%5Cimplies%20%5C%3A%20%20r%5E%7B2%7D%20%3D%20%20%5Cfrac%7B942%7D%7B3.14%20%7B%289%29%20%7D%20%7D%20%5C%5C%20%20%5C%5C%20%20%5Cimplies%20%5C%3A%20%20r%5E%7B2%7D%20%3D2700%20%5C%5C%20%20%5C%5C%20%20%5Cimplies%20%5C%3A%20%20r%3D%20%5Csqrt%7B2700%7D%20%20%5C%5C%20%20%5C%5C%20%20%5Cimplies%20%5C%3A%20%20r%3D51.96%20%5C%3A%20inches)
For this problem, we just have to use the values we're given to calculate the approximate value of pi.
The formula presented is
![\pi=Ar^{-2}](https://tex.z-dn.net/?f=%5Cpi%3DAr%5E%7B-2%7D)
When you have a negative exponent, we can use the following property
![a^{-b}=\frac{1}{a^b}](https://tex.z-dn.net/?f=a%5E%7B-b%7D%3D%5Cfrac%7B1%7D%7Ba%5Eb%7D)
Using this property, our problem turns out to be
![\pi=\frac{A}{r^2}](https://tex.z-dn.net/?f=%5Cpi%3D%5Cfrac%7BA%7D%7Br%5E2%7D)
Now, we just need to plug the given values on this equation
![\pi=\frac{50.265}{4^2}=3.1415625\approx3.142](https://tex.z-dn.net/?f=%5Cpi%3D%5Cfrac%7B50.265%7D%7B4%5E2%7D%3D3.1415625%5Capprox3.142)
The approximated value for pi is 3.142.