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Well, we know the slope-intercept is <span>y=5x-3 , now </span>
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reason why is called the slope-intercept form, so, the slope is 5, and we know the line runs through -2,-13, thus
![\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ -2 &,& -13~) \end{array} \\\\\\ % slope = m slope = m\implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-13)=5[x-(-2)] \\\\\\ y+13=5(x+2)](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26%26%28~%20-2%20%26%2C%26%20-13~%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%20m%5Cimplies%205%0A%5C%5C%5C%5C%5C%5C%0A%25%20point-slope%20intercept%0A%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-%28-13%29%3D5%5Bx-%28-2%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay%2B13%3D5%28x%2B2%29)
reason why is called the slope-intercept form, so, the slope is 5, and we know the line runs through -2,-13, thus