NEED HELP FAST. If anybody is great with Geometry or Physical Science, PM me.

Physics

1 answer:

liubo4ka [24]3 years ago

4 0

Answer:

Explanation:

I say it's B because I eliminated answers. A is wrong because the mass of an electron is 5.489×10−4 and the mass of a proton and neutron is 1.674929 x 10-27 kg. It's not C because the mass of a proton and neutron is greater than an electrons. Therefore it's B is greater

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Dennis_Churaev [7]

What is the question

5 0

3 years ago

A 4000-kg car bumps into a stationary 6000kg truck. The Velocity of the car before the collision was +4m/s and -1m/s after the c

Goryan [66]

Answer:

<em>The velocity of the truck is 3.33 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

$P=m_1v_1+m_2v_2+...+m_nv_n$

If some collision occurs, the velocities change to v' and the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

In a system of two masses:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2$

There are two objects: The m1=4000 Kg car and the m2=6000 Kg truck. The car was moving initially at v1=4 m/s and the truck was at rest v2=0. After the collision, the car moves at v1'=-1 m/s. We need to find the velocity of the truck v2'. Solving for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$