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Svetllana [295]
3 years ago
8

A geometric progression is a sequence of numbers in which each value (after the first) is obtained by multiplying the previous v

alue in the sequence by a fixed value called the common ratio. for example the sequence 3, 12, 48, 192, ... is a geometric progression in which the common ratio is 4. given the positive integer ratio greater than 1, and the non-negative integer n, create a list consisting of the geometric progression of numbers between (and including) 1 and n with a common ratio of ratio. for example, if ratio is 2 and n is 8, the list would be [1, 2, 4, 8]. associate the list with the variable geom_prog.
Mathematics
1 answer:
Fittoniya [83]3 years ago
4 0

The geometric progression with common ratio as 'r', first term as 'a' and nth term as 'n' is a,ar,ar^{2}, ar^{3},.....ar^{n-1}.

Let the common ratio(r) be 3 and n be 27.

Let the first term(a) of the sequence = 1

Second term of the sequence= ar= 1 x 3= 3

Third term of the sequence= ar^{2}= 1 x 3^{2}= 9

Fourth term of the sequence= ar^{3}= 1 x 3^{3}= 27

So, the list of numbers with r=3 and n=27 is [1,3,9,27].

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Trigonometric identities assignment 4
kykrilka [37]

Answer:

<em>Answer: choice D.</em>

Step-by-step explanation:

<u>Trigonometric Functions</u>

We need to recall some properties and definitions of the trigonometric functions.

\displaystyle \tan \theta=\frac{\sin\theta}{\cos\theta}

\displaystyle \sec \theta=\frac{1}{\cos\theta}

We need to simplify the following expression:

5\sin\theta\sec\theta

Substituting the identity for the secant:

\displaystyle 5\sin\theta\sec\theta=5\sin\theta.\frac{1}{\cos\theta}

Operating:

\displaystyle 5\sin\theta\sec\theta=5\frac{\sin\theta}{\cos\theta}

Substituting the definition of the tangent:

\displaystyle 5\sin\theta\sec\theta=5\tan\theta

Correct choice D.

6 0
3 years ago
Solve this please show your work &lt;3
Nookie1986 [14]

Given:

The expression is

\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=

To find:

The simplified form of the expression.

Solution:

We have,

\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=

The expression \sqrt[3]{48} can be written as

\sqrt[3]{48}=\sqrt[3]{8\cdot 6}

\sqrt[3]{48}=\sqrt[3]{8}\cdot \sqrt[3]{6}       [\because \sqrt[3]{ab}=\sqrt[3]{a}\sqrt[3]{b}]

\sqrt[3]{48}=2\cdot \sqrt[3]{6}

\sqrt[3]{48}=2\sqrt[3]{6}

Therefore, \sqrt[3]{48}=\sqrt[3]{8\cdot 6}=2\sqrt[3]{6}.

5 0
3 years ago
2. The next Saturday, the two friends leave at the same time a ain, and Kiran jogs twice
gladu [14]

Answer:

the end by the finish line

5 0
2 years ago
Find the simple interest pay for 7 years on a $600 loan at 5% per year.
babunello [35]

The simple interest would be $210. I hope that helps!

6 0
3 years ago
__,__, 8.16,32,64 what is the arithmetic sequence?
seraphim [82]

Answer:

2,4,8,16,32,64

Step-by-step explanation:

There are a couple of ways one could approach this. The goal is to find out the factor by which the numbers are increasing. Looking at going from 8 -> 16, we have either added 8, or doubled 8. So the factor is either +8 or x2. Going from 16 -> 32, adding 8 no longer holds true, while multiplying by 2 (doubling 16) does. To confirm what we have found, we can further check our math by using the final two numbers, 32 -> 64, to confirm that the sequence pattern is to double the current number to achieve the next number.

Working backwards, we can half each number to find out the first two numbers in the sequence. 64/2 = 32, 32/2 = 16, 16/2 = 8, 8/2 = 4, 4/2 = 2

8 0
3 years ago
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