To check for continuity at the edges of each piece, you need to consider the limit as approaches the edges. For example,
has two pieces, and , both of which are continuous by themselves on the provided intervals. In order for to be continuous everywhere, we need to have
By definition of , we have , and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
3x-132=0
you need to add all like terms first then answer the equation
Writing the two equations in full and subtracting R(x) from W(x) to arrive at D (x) gives the answer. This is shown below;
W(x) = 0.002x^3 - 0.01x^2 + 0x + 0
R (x) = 0x^3 + x^2 - 4x +13 -
-----------------------------------------------
D(x) = 0.002x^3 -1.01x^2 + 4x - 13
The answer is 162 81pi/2
Hope this helps!
the area is (1/2) x pix 9^2 = 81pi over 218.9=162162-81pi over 2