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Inga [223]
3 years ago
7

Can you help me with number 14 please

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0
Let the regular price be p.  Then the new price, after a 35% markdown, is 0.65p.

Mult. $3.29 by 0.65,  Result:  $2.14.  No match here.
 Mult. $4.19 by 0.65.  Result:  $2.72.  We've got a match here!
Mult. $2.79 by .65.  Result:  $1.81.  No match here.
Mult. $3.09 by .65.  Result:  $2.01.  Match!
 
And so on. 
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If 6x + 4 = 11x - 21, what is the value of x?
WITCHER [35]

Answer:

x = 5

Step-by-step explanation:

11x - 6x = 4 + 21

5x = 25 (÷5)

x = 5

7 0
3 years ago
Read 2 more answers
What is the value of P(9.1)? What does it tell us about the side length and perimeter
nadya68 [22]

Answer:

the answer is 36.4

Step-by-step explanation:

you have to multiply it by 4 so it it will look like this 9.1*4=36.4

4 0
3 years ago
For the diagram below, form an equation and then solve it to calculate the value of x
Talja [164]
You apply the sum of interior angles formula ie. (n-2)180. n=number of sides
since a pentagon has 5 sides it will be (5-2)180=540.
now add everything. x-5+x-6+2x-7+x+2x-2=540.
Solve for x: 7x-20=540
7x=540+20
7x=560
x=560/7
x=80
8 0
3 years ago
A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive
Leya [2.2K]

If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.

Calculation for the Amount of IV

It is given that,

1L IV contains 60meq of kcal

⇒ 1000 mL of IV contains 60meq of kcal

⇒ 1 mL of IV will contain 60 / 1000 meq of kcal

As per the question,

The amount of IV infused in the patient = 400 mL

⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)

= 4 × 6

= 24 meq of kcal

Hence, the patient receives 24meq of kcal amount of IV.

Learn more about amount here:

brainly.com/question/4567186

#SPJ1

6 0
2 years ago
(8.166×10^8)×(1.515×10^9)
loris [4]
The answer is ....1.237149 x 10^18
4 0
3 years ago
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