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Marizza181 [45]
3 years ago
12

When the outliers are removed, how does the mean change? (2 points)

Mathematics
1 answer:
quester [9]3 years ago
5 0

Answer:

Option 3: mean increases by 3

Step-by-step explanation:

Current mean:

[50+76+78+2(79)+80+81+2(82)+83] ÷ 10

= 77

Without the outliers:

[76+78+2(79)+80+81+2(82)+83] ÷ 9

= 80

80 - 77 = 3 (increase)

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A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery servic
sineoko [7]

Answer:

55.32% probability that a late package was delivered by express delivery service 2

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Late delivery.

Event B: Service 2 was used.

A certain company sends 35% of its overnight mail parcels via express delivery service 1 and the rest by express delivery service 2.

100 - 35 = 65%.

So P(B) = 0.65

Service 2 has a record of 2.0% of packages being delivered late.

This means that P(A|B) = 0.02

Probability of a late delivery.

35% from service 1. Of those, 3% are late.

65% from service 2. Of those, 2% are late.

So

P(A) = 0.35*0.03 + 0.65*0.02 = 0.0235

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55.32% probability that a late package was delivered by express delivery service 2

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