<span>In general, on the periodic table, the ionic radius of an element increases moving from top to bottom of the table. Ionic radius decreases moving from left to right. So, this effect would be the same for both metals and non metals.</span>
Answer:
Twice as much... => 11.9 mole CO₂
Explanation:
From balanced equation ...
2 moles C₂H₆ => 4 moles CO₂ then
5.95 moles C₂H₆ => 2(5.95) moles CO₂ = 11.9 mole CO₂
Answer: 8.88g
Explanation:Please see attachment for explanation
Answer:
Chlorine
Explanation:
Even though chlorine is highly electronegative, the best answer is no, and in this class we will consider chlorine not to form hydrogen bonds (even though it has the same electronegativity as oxygen). This is because chlorine is large and its lone electron is in a diffuse orbital, covering a large area, and thus do not have the high charge density to act as a strong hydrogen bond acceptor. But it does form weak hydrogen bonds in solid crystalline hydrogen chloride at very low temperatures.
Answer:
Aqueous NaOH: <u>soluble
</u>
Aqueous NaHCO₃: <u>insoluble</u>
Aqueous Na₂CO₃: <u>soluble</u>
Explanation:
The organic acid is insoluble. Its salt (ionic) is soluble.
The important principle is:
If you have two acids in a flask, the stronger acid (smaller pKₐ) will protonate the weaker one. The stronger acid will become ionic and therefore more soluble.
1. In NaOH
Let's write the formula for 4-nitrobenzoic acid as HA.
The equation for the reaction is
HA + OH⁻ ⇌ A⁻ + H₂O
pKₐ: 7.15 15.7
HA is the stronger acid. It will protonate the hydroxide ion and be converted to the soluble 4-nitrobenzoate ion.
4-Nitrophenol is soluble in NaOH.
2. In NaHCO₃
HA + HCO₃⁻ ⇌ A⁻ + H₂CO₃
pKₐ: 7.15 6.36
HCO₃⁻ is the stronger acid. It will protonate 4-nitrophenol.
4-Nitrobenzoic acid is insoluble in NaHCO₃.
3. In Na₂CO₃
HA + CO₃²⁻ ⇌ A⁻ + H₂CO₃
pKₐ: 7.15 10.33
HA is the stronger acid. It will protonate the carbonate ion.
4-Nitrophenol is soluble in Na₂CO₃.