Answer:
The answer to your question is
1.-Fe₂O₃
2.- 280 g
3.- 330 g
Explanation:
Data
mass of CO = 224 g
mass of Fe₂O₃ = 400 g
mass of Fe = ?
mass of CO₂
Balanced chemical reaction
Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂
1.- Calculate the molar mass of Fe₂O₃ and CO
Fe₂O₃ = (56 x 2) + (16 x 3) = 160 g
CO = 12 + 16 = 28 g
2.- Calculate the proportions
theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90
experimental proportion Fe₂O₃ / CO = 400/224 = 1.78
As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.
3.- 160 g of Fe₂O₃ --------------- 2(56) g of Fe
400 g of Fe₂O₃ --------------- x
x = (400 x 112) / 160
x = 280 g of Fe
4.- 160 g of Fe₂O₃ --------------- 3(44) g of CO₂
400 g of Fe₂O₃ -------------- x
x = (400 x 132)/160
x = 330 gr
Answer:
Explanation:
S is in 3d period, so it has 3 levels
1 level has 2 electrons, 2d level 8 electrons, 3d level 6 electrons
Answer:
1000 µL; 10 µL
Explanation:
A p1000 micropipet is set to dispense 1000 µL.
A p10 micropipet set to dispense 10 µL.
An ion is not a particle within the atoms
Answer:
The potential energy is 9800 J.
Explanation:
given information:
mass, m = 50 kg
height, h = 20 m
to calculate the potential energy, we can use the following formula
PE = mgh
where
PE = potential energy (Joule)
m = mass (kg)
h = height (m)
g = gravitational constant (9.8 m/s²)
so,
PE = mgh
= 50 x 9.8 x 20
= 9800 J
