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prisoha [69]
3 years ago
13

Please help ASAP! BRAINLIEST to best/right answer!

Mathematics
1 answer:
attashe74 [19]3 years ago
5 0
HI !

The lower quartile is 2
Answer C
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Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
• a helicopter hovering at 10 m above the ground is shining a spotlight at a person 30 m away1 . if the person is 2 m tall how l
pshichka [43]

As shown in the figure

Height of helicopter above the ground=30 m

Distance from the base to the point where the person is standing=30 m

height of the person=2 m

Now the person cast the shadow of length x m.

Triangle ABC and triangle EDC are similar.

∵ ∠B= ∠D=90°

∠C is common.

So by AA similarity ΔABC and ΔEDC are similar.

As we know when triangles are similar their sides are proportional.

AB/AD =BC/DC

Let DC=x meter

⇒\frac{10}{x}=\frac{30+x}{x}

⇒5=\frac{30+x}{x}[/tex]

⇒5x=30+x

⇒4x = 30

⇒ x=30/4

⇒ x=7.5 meter

So length of shadow=7.5 meter

2. volume of a sphere of radius r is v (r) =\frac{4}{3}π r^{3}

\frac{\mathrm{d} }{\mathrm{d} r}V=4/3π×3r^2

       =4πr^2


surface area of a sphere of radius r is 4πr^2

b)  Ratio of derivative of volume of sphere to surface area of sphere=\frac{4\pi r^2}{4\pi r^2}

             =1  [ incomplete question but you have written few words ]

4 0
2 years ago
PLEASE HELP! giving BRAINLIEST AND GIVE CORRECT ANSWER AND EXPLAIN!
11111nata11111 [884]

The exercise is basiacally asking for the perimeter of the garden. The perimeter of a rectangle is twice the sum of its dimensions, so we have

P=2(6+11)=2\cdot 17=34

7 0
3 years ago
15PTS!!!! HELPPPP!!! Determine the length of fencing around an 80 m by 170 m rectangular playing field if fence is to be 25 m ou
marshall27 [118]
Perimeter=2L+2W, in this case L=80+2(25) and W=170+2(25) so

P=2(L+W)=2(80+50+170+50)

P=2(350)=700m
5 0
3 years ago
Timed quiz help please! <br> 2 2/5 kilometers in 3 3/4 minuets.
shepuryov [24]

Answer: 16/25 (sorry I'm not really sure bc I'm just  a middle schooler)

Step-by-Step explanation:

2 2/5 km=2.4 kilometers

3 3/4 minutes=3.75 minutes

2.4/3.75=240/375

240/375=48/75=16/25=64/100=0.64

0.64 km/minute (0.64 km per minute)

you can solve the problem using the fractions...

2 2/5=12/5

3 3/4=15/4

(12/5)/(15/4)=(12/5)*(4/15)=48/75=16/25=0.64 again, or you can simplify before multiplying...

(12/5)/(15/4)=(12/5)*(4/15)=(4/5)*(4/5)=16/25...

4 0
2 years ago
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