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zvonat [6]
2 years ago
15

Determine if the following sequence is an Arithmetic Sequence. If it is, what would be the 31st term? NOTE: an=a1+(n-1)d

Mathematics
2 answers:
notsponge [240]2 years ago
4 0

Answer:

The arithmetic sequence of 31st term is 127.

Step-by-step explanation:

Here's the required formula to find the arithmetic sequence :

\longrightarrow\pmb{\sf{a_n = a_1 + (n - 1)d}}

  • \pink\star aₙ = nᵗʰ term in the sequence
  • \pink\star a₁ = first term in sequence
  • \pink\star n = number of terms
  • \pink\star d = common difference

Substituting all the given values in the formula to find the 31st term of arithmetic sequence :

\leadsto{\sf{ \:  \: a_n = a_1 + (n - 1)d}}

\leadsto{\sf{ \:  \: a_{31} = 7+ (31- 1)4}}

\leadsto{\sf{ \:  \: a_{31} = 7+ (30)4}}

\leadsto{\sf{ \:  \: a_{31} = 7+ 30 \times 4}}

\leadsto{\sf{ \:  \: a_{31} = 7+ 120}}

\leadsto{\sf{ \:  \: a_{31} =127}}

\star \:  \:  \pink{\underline{\boxed{\sf{\purple{a_{31} =127}}}}}

Hence, the arithmetic sequence of 31st term is 127.

\rule{300}{2.5}

Ivan2 years ago
3 0
<h3>Key points :-</h3>

᪥ The formula to find the 31st term is : \sf \: a_{n} =  a_{1} + (n - 1) \times d

᪥ In the formula, \sf \: a_{1} represents the first term of the sequence.

᪥ \sf\:n is the number of terms, In our case n is 31.

᪥ \sf\:d is the common difference between the terms, In our case d is 4.

\green{ \rule{300pt}{3pt}}

<em>Detailed Solution is attached</em>᭄

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Read 2 more answers
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
3 years ago
PLEASE HELP THANK YOU
arsen [322]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Similarities.

Since here, first figure is a Triangle, hence similarity of a triangle is given by ratio of it sides and make them equate,

hence for,

1.) 16/12 = x/9 ===> 4/3 = x/9 ===> x = 9*4/3 ==> x = 36/3

hence the value of x is 12 , ===> x = 12 .

2.) here,in the case of a Reactangle the relation is such that, length = 2* breadth,

hence we apply the relation,

x = 2*4.5 ===> x = 9 units.

5 0
3 years ago
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