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zvonat [6]
2 years ago
15

Determine if the following sequence is an Arithmetic Sequence. If it is, what would be the 31st term? NOTE: an=a1+(n-1)d

Mathematics
2 answers:
notsponge [240]2 years ago
4 0

Answer:

The arithmetic sequence of 31st term is 127.

Step-by-step explanation:

Here's the required formula to find the arithmetic sequence :

\longrightarrow\pmb{\sf{a_n = a_1 + (n - 1)d}}

  • \pink\star aₙ = nᵗʰ term in the sequence
  • \pink\star a₁ = first term in sequence
  • \pink\star n = number of terms
  • \pink\star d = common difference

Substituting all the given values in the formula to find the 31st term of arithmetic sequence :

\leadsto{\sf{ \:  \: a_n = a_1 + (n - 1)d}}

\leadsto{\sf{ \:  \: a_{31} = 7+ (31- 1)4}}

\leadsto{\sf{ \:  \: a_{31} = 7+ (30)4}}

\leadsto{\sf{ \:  \: a_{31} = 7+ 30 \times 4}}

\leadsto{\sf{ \:  \: a_{31} = 7+ 120}}

\leadsto{\sf{ \:  \: a_{31} =127}}

\star \:  \:  \pink{\underline{\boxed{\sf{\purple{a_{31} =127}}}}}

Hence, the arithmetic sequence of 31st term is 127.

\rule{300}{2.5}

Ivan2 years ago
3 0
<h3>Key points :-</h3>

᪥ The formula to find the 31st term is : \sf \: a_{n} =  a_{1} + (n - 1) \times d

᪥ In the formula, \sf \: a_{1} represents the first term of the sequence.

᪥ \sf\:n is the number of terms, In our case n is 31.

᪥ \sf\:d is the common difference between the terms, In our case d is 4.

\green{ \rule{300pt}{3pt}}

<em>Detailed Solution is attached</em>᭄

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Step-by-step explanation:

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3 years ago
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Ugo [173]

Answer:

L\left(te^{2t }sin3t\right)=\frac{6s-12}{(s^2-4s+13)^2}.

Step-by-step explanation:

If F(s)= L{f(t)}

Then L\left\{(t^nf(t)\right\}=(-1)^n\frac{\mathrm{d^n}F(s)}{\mathrm{d^n}s}

L\left\{te^{2t}sin3t\right\}

f(t)=e^{2t}sin3t

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L\left\{te^{2t}sin3t\right}=-\frac{\mathrm{d}F(s)}{\mathrm{d}s}

=-\frac{\mathrm{d}e^{2t}sin3t}{\mathrm{d}s}

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