Answer:
(B) Boreal owls range over larger areas in regions where food of the sort eaten by small mammals is sparse than they do in regions where such food is abundant
Explanation:
Living beings exhibit various changes in the behavior and niche to make themselves better fitted to the conditions of their habitats.
Boreal owls feed on the other smaller mammals such as mice and shrews. These organisms that serve as their prey are relatively less abundant in the habitat. To ensure the food availability, the boreal owls occupy a larger area so that they can catch their less abundant food organisms.
In the habitats where the prey species of boreal owls are present in a larger number, these owls occupy smaller regions since the food organisms are easily available.
Answer: for HCO it dissolves in water
for CH2OH IT dissolves in water
Explanation:
i just took the test
Increasing salinity<span> also increases the </span>density<span> of sea </span>water<span>. Less dense </span>water<span> floats on top of more dense </span>water<span>. Given two layers of </span>water<span> with the same </span>salinity<span>, the warmer </span>water<span> will float on top of the colder </span>water<span>. ... </span>Temperature<span> has a greater </span>effect<span> on the </span>density<span> of </span>water<span> than </span>salinity<span> does</span>
Answer: the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3
Explanation:
We know that; Gram negative bacteria looks pale reddish in color under a light microscope from Gram staining.
therefore
There are 30 red bacterial colonies counted.
1 mL of from tube 1 was removed and added to tube with 99 mL saline (tube 2) dilution is 1/100.
transferred volume into the plate is 1 mL.
Now, we have to determine the cfu/g Gram-negative bacteria in the fecal sample
Formula to calculate CFU/g bacteria in fecal sample is expressed as;
C = n/(s×d )
where C is concentration (CFU/g)
, n is number of colonies
, s is volume transferred to plate
, d is dilution factor.
so we substitute
C = 30 / ((1/100) × 1)
C = 30 / 0.01
C = 3000
C = 3.0 × 10^3
THERFERE, the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3
Some scientists hypothesize that the eukaryotic cells are really the result of symbiotic processes!
Specifically, the internal organs of the cells could be a remnant of a symbiotic relationship in which one cell lived inside of another cell. These two cells then both split upon reproduction and eventually the cell inside was reduced to an organelle.
But according to this theory, it is very likely that the prokaryotic cells engaged in a number of symbiotic relationship, and that this actually lead to the emergence of eukaryotic cells!
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