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grin007 [14]
3 years ago
14

What type of camera is a cell phone camera

Computers and Technology
2 answers:
mezya [45]3 years ago
7 0

Answer:The first camera phone was the Kyocera Visual Phone VP-210, released in Japan in May 1999. The camera had a 110,000-pixel front-facing camera.

Explanation:

Sergeeva-Olga [200]3 years ago
3 0

Answer:

A camera phone is a mobile phone which is able to capture photographs and often record video using one or more built-in digital cameras. It can also send the resulting image over the telephone function. The first commercial camera phone was the Kyocera Visual Phone VP-210, released in Japan in May 1999.

Explanation:

Hope this kinda helps you :)

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What is Microsoft first product
Alenkasestr [34]

Answer:  Xenix

Explanation:

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3 years ago
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How do you hack a iPhone, Like If you forgot your password and want to get back in your phone. What do you do?
s344n2d4d5 [400]

Answer:

fix it on itunes

Explanation:

or get a new one

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Which term is used to identify the connection of computers that are physically close to one another?
marta [7]

Answer: Local Area Network (LAN)

Explanation:

A Local Area Network (LAN) is a computer network that interconnects computers within a limited physical area such as a residence, school, laboratory, university campus or office building.

An example of  LAN network is "Phone, Computer and TV connected to a single network (such as a Home Network) via Cables, Wifi, Bluetooth or Hotspot". When the devices are interconnected or connected to a LAN, it becomes accessible between each other.

A simplest example of a LAN Device is a <em>Home Router.</em>

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3 years ago
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Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
5) Write a regular expression would zip code + 4 fields of the forms: xxxxx-xxxx where x is any number but the last 4 digits cou
marusya05 [52]

Answer:

Following is the expression written in "Bash script" (mixture of commands):

^\d{5}(?:[-\s]\d{4})?$

Explanation:

  • ^ = For staring string (denotation).
  • \d{5} = Matching 5 digits (first five unknown x's)
  • (?:…) = Making Group (making group of former 5 digits)
  • [-\s] = Match a hyphen  or a space

                 (checking if a hyphen is present?)

  • \d{4} = Matching 4 digits (next four unknown x's)
  • …? = Pattern before it is optional
  • $ = Ending of the string.(denotation)

4 0
3 years ago
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