The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
c) (x + 2)(x + 2i)(x - 2i)
Step-by-step explanation:
x^3 + 2x^2 + 4x + 8
= (x^3 + 2x^2) + (4x + 8)
= x^2( x + 2) + 4(x + 2)
= (x + 2)(x^2 + 4)
= (x + 2)(x^2 - 4i^2) ---------------------------->(i^2 = -1)
= (x + 2)(x + 2i)(x - 2i)
The 99 percent confidence interval for the true mean length of the bolt is CI = (2.8712, 3.1288)
<h3>How to find the confidence interval?</h3>
Confidence Interval is used to tell us the degree of certainty or uncertainty that is existent in a sampling method.
The general formula for confidence interval is;
CI = x' ± z(s/√n)
where;
x' is sample mean
z is z-score at confidence level
s is sample standard deviation
n is sample size
We are given;
sample size; n = 36
Sample mean; x' = 3 inches
standard deviation; s = 0.3 inches
confidence level = 99%
z at 99% CL = 2.576
Thus;
CI = 3 ± 2.576(0.3/√36)
CI = 3 ± 0.1288
CI = (2.8712, 3.1288)
Read more about Confidence Interval at; brainly.com/question/17097944
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Answer: 37) 170
Step-by-step explanation:
85 - (-85) = 85 + 85 = 170
