In ΔIJK, ∠K \cong≅∠J, IJ = 9 and JK = 10. Find the length of KI.

Mathematics

1 answer:

MArishka [77]3 years ago

8 0

Answer:

KI = 9

Step-by-step explanation:

Given that triangle IJK has two equal base angles, angle J and angle K, this meets the definition of an isosceles triangle.

An isosceles triangle has two equal angles. Therefore, the side lengths opposite each of the equal base angles of ∆IJK would be of equal lengths.

Given that IJ which corresponds to angle K = 9, and JK, which corresponds to the other 3 angle, therefore, the length of KI which corresponds to angle J would be the same length as the length of IJ = 9.

<k is congruent to <J

IJ = 9, therefore, IJ = KI

KI = 9.

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Svet_ta [14]

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You are right!!!

Step-by-step explanation:

The transpose of a matrix is simply a flipped version of the original matrix. We can transpose a matrix by switching its rows with its columns.

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