In ΔIJK, ∠K \cong≅∠J, IJ = 9 and JK = 10. Find the length of KI.
1 answer:
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The function is 
, and according to the description of the function in the problem statement, we have the following:
at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:
(ft), which is the initial height, as expected.
At t=1 (sec), the height would be
.
etc.
The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.
This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.
Answer: B) 7 sec
at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:
At t=1 (sec), the height would be
etc.
The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.
This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.
Answer: B) 7 sec
Data:
Formula: diameter = 2*radius
Formula: (<span>Circle length)
</span>
<span>
Solving: </span><span>Using the data
</span>diameter = 2*radius
20 = 2*r
2r = 20
<span>Now, replace in the circumference length formula
</span>
Answer:
<span>The exact circumference of the circle is </span>
Formula: diameter = 2*radius
Formula: (<span>Circle length)
</span>
<span>
Solving: </span><span>Using the data
</span>diameter = 2*radius
20 = 2*r
2r = 20
<span>Now, replace in the circumference length formula
</span>
Answer:
<span>The exact circumference of the circle is </span>