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aleksandr82 [10.1K]
3 years ago
8

Oh pls help I have a test tomorrow

Mathematics
1 answer:
yaroslaw [1]3 years ago
8 0

Answer:

you would write it as -3.25 as a whole number

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Kryger [21]

Answer:

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3 years ago
Solve the inequality −22 + 4q &gt; 2
Mars2501 [29]

First you had to add by twenty-two from both sides of equation form.

-22+4q+22>2+22

Then simplify by equation.

4q>24

Next, you divide by four from both sides of equation form.

\frac{4q}{4}> \frac{24}{4}

Finally, simplify by equation.

24/4=6

24/6=4

6*4=24

4*6=24

q>6

Final answer: \boxed{q>6}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

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8 0
3 years ago
What is the range of F(x)=72x-x^2
Marianna [84]

Answer:

Range of F(x) = (-∞ ,72).

Step-by-step explanation:

Range of the function F(x) means the set of values which are taken by the function along its domain.

F(x) = 72 - x^{2}

Since coefficient of x^{2} is negative on the right side ,

Maximum value of F(x) will come at x = 0.

Which is, F(0) = 72.

Now, as x increases , F(x) decreases , when x will reach infinity ,

F(x) will be reaching negative of infinity .

Thus, F(x) is ranging from -∞ to 72 .

Range of F(x) = (-∞ ,72).

3 0
3 years ago
Select the equation written in point-slope form.
slavikrds [6]
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4 0
3 years ago
For a project in his Geometry class, Mamadou uses a mirror on the ground to measure the height of his school's football goalpost
andreev551 [17]

Answer:

Height of the goalpost is 9.25 m.

Step-by-step explanation:

As per the rule of reflection in physics,

Angle of incidence = Angle of reflection

As we can see in the picture attached, both the angles (θ) are equal.

m∠ACB = m∠ECD = 90° - θ

m∠ABC = m∠ADC = 90°

Therefore, both the triangles ΔABC and ΔEDC will be similar.

And by the property of similar triangles, their corresponding sides will be proportional.

\frac{AB}{ED}= \frac{CB}{CD}

\frac{1.75}{ED}=\frac{2.6}{13.75}

ED = \frac{1.75\times 13.75}{2.6}

ED = 9.25 m

Height of the goalpost is 9.25 m.

4 0
2 years ago
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