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IRISSAK [1]
3 years ago
7

Enter the equation of the circle described below. Center (0, 4), radius sqrt 3

Mathematics
2 answers:
irakobra [83]3 years ago
6 0
Equation of a circle is:
(x - h)^2 + (y - h)^2 = r^2

where (h, k) is the center and r = radius

put in n the values given
(x - 0)^2 + (y - 4)^2 = (sqrt(3))^2
x^2 + (y - 4)^2 = 3
Rasek [7]3 years ago
5 0

Answer:

x^2 + (y - 4)^2 = 3

Step-by-step explanation:


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The area of an equilateral triangle is given by A =3^1/2/4s^2. Find the length of the side s of an equilateral triangle with an
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Answer:

The length of the side of an equilateral traingle s=2\sqrt{2} inches

Step-by-step explanation:

Given that the area of an equilateral triangle is given by

A=3^\frac{1}{2}s^2

It can be written as

a=\frac{\sqrt{3}}{4} s^2 Square inches        (1)

To find the length of the side s os an equilateral triangle

Given that area of an equilateral triangle is 12^\frac{1}{2} square inches

It can be written as

A=12^\frac{1}{2}

A=\sqrt{12} square inches

It can be written as

A=12^\frac{1}{2}

A=\sqrt{12} square inches           (2)

Now comparing equations (1) and (2) we get

\frac{\sqrt{3}}{4}s^2=\sqrt{12}

\frac{\sqrt{3}}{4}s^2=\sqrt{4\times 3}

Dividing by \frac{\sqrt{3}}{4} on both sides we get

\frac{\frac{\sqrt{3}}{4}s^2}{\frac{\sqrt{3}}{4}}=\frac{2\sqrt{3}}{\frac{\sqrt{3}}{4}}

\frac{\sqrt{3}}{4}s^2\times\frac{4}{\sqrt{3}}=2\sqrt{3}\times\frac{4}{\sqrt{3}}

s^2=8

s=\sqrt{8}

Therefore s=2\sqrt{2} inches

Therefore the length of the side of an equilateral traingle s=2\sqrt{2} inches

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How many tens and ones in the number 82?
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Find the greatest common factor of 10 and 125.
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Answer:

5

Step-by-step explanation:

10 = 2 * 5

125 = 5 * 5 * 5

Taking out the duplicates from the  2 lists :-  GCF = 5

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Step-by-step explanation:

sinx=(opposite side)/(hypotenuse)

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A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

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3 years ago
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