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amm1812
3 years ago
6

The area of an equilateral triangle is given by A =3^1/2/4s^2. Find the length of the side s of an equilateral triangle with an

area of 12^1/2 square inches.
Mathematics
1 answer:
yan [13]3 years ago
3 0

Answer:

The length of the side of an equilateral traingle s=2\sqrt{2} inches

Step-by-step explanation:

Given that the area of an equilateral triangle is given by

A=3^\frac{1}{2}s^2

It can be written as

a=\frac{\sqrt{3}}{4} s^2 Square inches        (1)

To find the length of the side s os an equilateral triangle

Given that area of an equilateral triangle is 12^\frac{1}{2} square inches

It can be written as

A=12^\frac{1}{2}

A=\sqrt{12} square inches

It can be written as

A=12^\frac{1}{2}

A=\sqrt{12} square inches           (2)

Now comparing equations (1) and (2) we get

\frac{\sqrt{3}}{4}s^2=\sqrt{12}

\frac{\sqrt{3}}{4}s^2=\sqrt{4\times 3}

Dividing by \frac{\sqrt{3}}{4} on both sides we get

\frac{\frac{\sqrt{3}}{4}s^2}{\frac{\sqrt{3}}{4}}=\frac{2\sqrt{3}}{\frac{\sqrt{3}}{4}}

\frac{\sqrt{3}}{4}s^2\times\frac{4}{\sqrt{3}}=2\sqrt{3}\times\frac{4}{\sqrt{3}}

s^2=8

s=\sqrt{8}

Therefore s=2\sqrt{2} inches

Therefore the length of the side of an equilateral traingle s=2\sqrt{2} inches

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