All categories

3 years ago

Suppose there is no outcome common to all three of the events A, B, and C.

Mathematics

1 answer:

mina [271]3 years ago

6 0

Answer:

Yes, the event are mutually exclusive...

Step-by-step explanation:

Event are mutually exclusive if those event cannot occur at the same time. That is the definition of mutually exclusive for instance in a football match, a certain team canot score 0 and 2goals in a match, it is either he scored 2goals or zero goals... In a throw of a coin we cannot have head and tail at the same time, it is either we have a head or a tail, all the event are mutually exclusive.

Now if we have a dealer selling blue car and two doors car. Let say 20% are blue and 10% have two doors. Then, this are not mutually exclusive because we can have a car that is blue and have two doors.

Mutually exclusive events are like disjoint set in SET theory, where A intersection B intersection C is equal to empty set.

Where A n B n C= {} empty set

You might be interested in

Which table shows a proportional relationship?

lord [1]

To figure this out, always divide y by x in each table. All of the values have to be equal or the table isn’t proportional.

In this case, the last choice is proportional.

7 0

3 years ago

A poker hand consisting of 7 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl

77julia77 [94]

Answer:

The probability is 2,010,580/13,378,456

Step-by-step explanation:

Here is a combination problem.

We want to 7 cards from a total of 52.

The number of ways to do this is 52C7 ways.

Also, we know there are 12 face cards in a standard deck of cards.

So we are selecting 3 face cards from this total of 12.

So also the number of cards which are not face cards are 52-12 = 40 cards

Out of all these 40, we shall be selecting exactly 4. The number of ways to do this 40C4

Thus, the required probability will be;

(40C4 * 12C3)/52C7 = (91,390 * 220)/133,784,560

= 20,105,800/133,784,560 = 2,010,580/13,378,456

7 0

4 years ago

Pumps a, b, and c operate at their respective constant rates. pumps a and b, operating simultaneously, can fill a certain tank i

MrMuchimi

Let a, b, and c be the times each pump will fill the tank when working alone.

Therefore, in 1 hour;

1/a +1/b = 1/(6/5) = 5/6 ---- (1)
1/a+1/c = 1/(3/2) = 2/3 ---- (2)
1/b+1/c = 1/(2) = 1/2 ---- (3)

From equation (1)
1/a = 5/6-1/b

Substituting for 1/a in eqn (2)
5/6-1/b+1/c = 2/3
-1/b +1/c = -1/6 => 1/c = 1/b - 1/6 --- (4)

Using eqn (4) in eqn (3)
1/b+1/b-1/6 = 1/2
2/b-1/6 = 1/2
2/b =1/2+1/6 = 2/3
1/b = 1/3
Then,
1/c = 1/3 - 1/6 = 1/6
1/a = 5/6 - 1/3 = 1/2

This means, in 1 hour and with all the pumps working together, the tank will be filled to;
1/a+1/b+1/c = 1/2+1/3+1/6 = 1 (filled fully).

Therefore, it will take 1 hour to fill the tank when all pumps are working together.

7 0

3 years ago

WRITE THE NEXT 2 TERMS OF EACH SEQUENCE

Helen [10]

Answer:

1) 2,6,18,54,162,468 (multiply by 3 each time)

2) 2, -4, 8, -16, 32, -64 (i'm not sure what this is but i'm pretty confident i'm right lol)

3) 1,3,5,7,9,11 (add 2 each time)

4) 1, 2/3 , 4/6 , 8/9 , _ _ (i'm sorry i tried my hardest but i don't know this one)

Step-by-step explanation:

hope this helped! so sorry about 4...

8 0

3 years ago

Read 2 more answers

Which equation matches this statement?

Mice21 [21]

A) x + .07x = 45.50

X is the price of the toy boat, •07x adds the tax for a total paid of $45.50

8 0

3 years ago