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SVETLANKA909090 [29]
3 years ago
6

Find the equation of the line which has slope of 5 and passes through the point (2,9)​

Mathematics
1 answer:
saul85 [17]3 years ago
5 0

Answer:

y = 5 x - 1

Step-by-step explanation:

Use the "point-slope" form of a line with slope m = 5 and going through the point (x1, y1) = (2, 9)

y - y1 = m (x - x1)

in our case:

y - 9 = 5 (x - 2)

distributive property to reduce the parenthesis:

y - 9 = 5 x - 10

adding 9 to both sides:

y = 5 x - 10 + 9

y = 5 x - 1

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The cup, on the 9th hole of a golf course, is located, dead center, in the middle of a circular green, which is 35 feet in radiu
ale4655 [162]

Answer:

± 27.33 ft

Step-by-step explanation:

For the given problem, we can estimate the initial and final coordinates of the line of the ball path as (-40,-50) and (0,0). Therefore, the slope is:

(-50-0)/(-40-0) = 50/40 = 1.25

Similarly, we can estimate the slope of a perpendicular line to the line of the ball path as: -1*(1/1.25) = -0.8.

Therefore, using (0,0) and the slope -0.8, the equation of the perpendicular line is: -0.8 = (y-0)/(x-0);

-0.8 = y/x

y = -0.8x

Furthermore, we are given the circle radius as 35 ft and we can use the distance formula to find the two points 35 ft far from the origin:

35^2 = x^2 + y^2

y = -0.8x

35^2 = x^2 + (-0.8x)^2

1225 = (x^2 + 0.64x^2)

1225 = 1.64x^2

x^2 = 1225/1.64 = 746.95

x = sqrt(746.95) = ± 27.33 ft

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Step-by-step explanation:

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