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SVETLANKA909090 [29]
3 years ago
6

Find the equation of the line which has slope of 5 and passes through the point (2,9)​

Mathematics
1 answer:
saul85 [17]3 years ago
5 0

Answer:

y = 5 x - 1

Step-by-step explanation:

Use the "point-slope" form of a line with slope m = 5 and going through the point (x1, y1) = (2, 9)

y - y1 = m (x - x1)

in our case:

y - 9 = 5 (x - 2)

distributive property to reduce the parenthesis:

y - 9 = 5 x - 10

adding 9 to both sides:

y = 5 x - 10 + 9

y = 5 x - 1

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love history [14]
It equals to 8.82 
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Change 1.4 to a fraction.
kifflom [539]

1.4 as a fraction is 1 4/10 (simplified to 1 2/5).

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Read 2 more answers
Use the distributive property to express 24+36
Lisa [10]

Answer:

all u have to do is break the numbers apart

Step-by-step explanation:

24. 36

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2 years ago
11. rewrite the function in the form y=a (1+r)*
Anettt [7]

Problem 10

The two functions <u>are inverses</u> of each other. Why? Because we can think of f(x) = (x-7)/(-2) as y = (x-7)/(-2).

Swap x and y to get x = (y-7)/(-2). Solving for y leads to y = -2x+7 showing that g(x) = -2x+7 is the inverse of f(x) = (x-7)/(-2). This process can be done in reverse to get the same result.

===================================================

Problem 11

y = a(6)^(t/2)

y = a( 6^(1/2) )^t

y = a(2.4494897)^t

y = a( b )^t

where b = 6^(1/2) = 2.4494897 approximately

Set b equal to 1+r and solve for r

1+r = 2.4494897

r = 2.4494897-1

r = 1.4494897

This rounds to about r = 1.45

The r value is the decimal form of the percentage, which means we move the decimal point over two spots to the right to get 145% approximately

Answers:

The equation is roughly y = a(1 + 1.4494897)^t

The growth rate is approximately 145%

===================================================

Problem 12

You have the correct answer. Nice work.

===================================================

Problem 13

You are very close to the correct answer. However, you're missing the base of the log.

The answer should be \log_{49}(343) = \frac{3}{2}. So you'll need to write in a small "49" under the log.

The general rule is that exponential equations in the form b^x = y are equivalent to the log version of \log_{b}(y) = x. For each equation, b is the base. The idea of logs is to isolate the exponent.

3 0
2 years ago
If f(x)=7x-6 which of the following is the inverse of (x)?
Vedmedyk [2.9K]

Here we have , f(x) = y= 7x-6

To find the inverse function of the given function, we need to follow some steps, which are:

First we need to switch x and y, that is

x= 7y-6

Next step is to solve for y, and for that, we need to add 6 to both sides

x+6=7y

Dividing both sides by 7, that is

y = \frac{x+6}{7}

Therefore,

f^{-1}(x)= \frac{x+6}{7}

3 0
3 years ago
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