When comparing and contrasting, it's always good to think about what your doing it with.
I'm not going to give to a full paragraph, but I'd love to help get one started for you!
First, let's look at the definition of both terms:
-Design: "<span>purpose, planning, or intention that exists or is thought to exist behind an action, fact, or material object" ~ Google
-Problem Solving: "Taking different approaches to finding a solution to the problem, or task at hand."
Now, let's compare. When designing things, you in a way, are problem solving to figure out how to create or build a solution to a problem. This can be through trial and error, or complex thinking.
I hope this helps, and good luck! :)</span>
Answer:
A = 57°
B = 19°
C = 104°
Step-by-step explanation:
We have a triangle with 3 angles:
A, B, and C.
We know that:
"Angle A is 3 times larger than angle B"
We can write this as:
A = 3*B
"Angle C was 10° less than 6 times angle B"
This can be written as:
C = 6*B - 10°
And we also know that the sum of all interior angles of a triangle is 180°
Then we also have the equation:
A + B + C = 180°
So we have a system of 3 equations:
A = 3*B
C = 6*B - 10°
A + B + C = 180°
To solve this, the first step is to isolate one of the variables in one of the equations.
We can see that A is already isolated in the first one, so we can skip that step.
Now we need to replace A in the other equations, to get:
C = 6*B - 10°
(3*B) + B + C = 180°
Now we have a system of two equations.
Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:
3*B + B + (6*B - 10°) = 180°
Now we can solve this for angle B
4*B + 6*B - 10° = 180°
10*B - 10° = 180°
10*B = 180° + 10° = 190°
B = 190°/10 = 19°
Now that we know the measure of angle B, we can input this in the equations:
A = 3*B
C = 6*B - 10°
To find the measures of the other two angles:
A = 3*19° = 57°
C = 6*19° - 10° = 104°
Answer:
The area of square in terms of x = 16x² -24x + 9
Step-by-step explanation:
It is stated in the question that the length of a square = 4x - 3
Formula to find the area of the square is
<h2 /><h2>Area = length²</h2><h2 />
Area = ( 4x - 3 )²
<em>by using ( a - b )² = a² + b² - 2ab</em>
here a = 4x and b = -3
So,
(4x)² + (-3)² - 2(4x)(3)
16x² + 9 - 2(12x)
16x² + 9 - 24x
16x² -24x + 9
The area of square in terms of x = 16x² -24x + 9
Answer:
Negative since the line is coming like this \
It gets to be negavite will if it was like this/ it could have been positive
Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:

a) 
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082

b) 
The area to the left of z=3.00 is 0.9987

c) The z-value of 1200 is 0
The area to the left of 0 is 0.5

The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e) 
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1