3 years ago

Round 51,487 to the nearest thousand

Mathematics

1 answer:

4vir4ik [10]3 years ago

4 0

Hey There!

51,487 rounded to the nearest thousand is 51,000

Thank You!

You might be interested in

jill is thinking of two numbers. they have the sum of 27 and a difference of 7. what are the two numbers?

bezimeni [28]

17 and 10/ 17+10=27 17-10=7

8 0

2 years ago

Read 2 more answers

Solve for possible values of x. 3x^2 = 18x

uysha [10]

(0,0) and (6,0)

First we subtract 18x from both sides

3x²-18x=0

Factor out a 3x

3x(x-6)=0

This means that x is either 0 or 6

7 0

3 years ago

Read 2 more answers

Please help with this question

insens350 [35]

Answer:

alternate interoir

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help me i will mark you brainliest

kozerog [31]

Answer:

it will be c

Step-by-step explanation:

4 0

3 years ago

The weights of red delicious apples are approximately normally distributed with a mean of 9 Ounces and a standard deviation of 0

Simora [160]

Answer:

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

Step-by-step explanation:

Let X: weight of a red delicious apple, and B: the weight of the box and packing material.

The distribution that will represent W: the total weight of the packaged 5 randomly selected apples will be also normally distributed.

Applying the property of the mean: $E(aX)=aE(X)$ , the mean of W will be:

$\mu_W=E(W)=E(5X+B)=5E(X)+E(B)=5*9+10=45+10=55$

Applying the property of the variance: $V(aX+b)=a^2V(X)$ , the variance of W will be:

$\sigma^2_W=V(W)=V(5X+B)=5^2V(X)+V(B)=25*0.75+0=18.75$

The mean standard deviation of W will be the squared root of V(W):

$\sigma_W=\sqrt{V(W)}=\sqrt{18.75}=4.33$

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

3 0

3 years ago