3 years ago

How many 3-digit numbers with all even digits.

1 answer:

6 0

For the first digit, you have 4 choices (2, 4, 6, 8); for the second and third digits, you have 5 choices (2, 4, 6, 8 and 0). So the total number of positive qualifying numbers is 4*5*5 = 100

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