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3 years ago

What is 3.56 x 10^-5 in standard form?

1 answer:

7 0

Well here is your first part...

3.56×10^-5

Its negative so go to the left:

=.00000356

Here is your second part...

4×10^4×3×10^4

There both positive so go to the right

=40000 =30000

Then you multiply....

40000×30000=

= 1200000000

Here's your third part...

You need to divide 31 by 117

31÷117=

=0.2650%

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Simplify 12^3/12^7<br> A. 12^4<br> B 1/12^4<br> C 1/12^-4<br> D 12^10

mrs_skeptik [129]

The answer is B.

Explanation:

If you divide exponents, you subtract the exponents.

8 0

3 years ago

Read 2 more answers

Weights of American adults are normally distributed with a mean of 180 pounds and a standard deviation of 8 pounds. What is the

ahrayia [7]

Answer:

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 180, \sigma = 8$

What is the probability that a randomly selected individual will be between 185 and 190 pounds?

This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So

X = 190

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{190 - 180}{8}$

$Z = 1.25$

$Z = 1.25$ has a pvalue of 0.8944

X = 185

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{185 - 180}{8}$

$Z = 0.63$

$Z = 0.63$ has a pvalue of 0.7357

0.8944 - 0.7357 = 0.1587

15.87% probability that a randomly selected individual will be between 185 and 190 pounds

3 0

2 years ago

Jennie has 7 tickets for carnival rides. The Ferris wheel costs 4 tickets, The roller coaster costs 6 tickets. the merry-go-roun

algol13

Answer: 6

Step-by-step explanation:

7 - 3 = 4

3 - 4 = 0

0 - 6 = -6

6 0

3 years ago

YESSS love struggling 7th grade math problem ......... help me

Dimas [21]

Answer:

x = 20

ABC = 85

BCA = 81

CAB = 14

Step-by-step explanation:

I answered your other question, so basically just read the explanation there cuz I'm too lazy to write it again :P

4 0

2 years ago

Urgent!! Will mark brainliest!!

horsena [70]

Answer:

1) x is negative and y is positive ⇒ last answer

2) cotФ = -12/35 ⇒ second answer

3) The right identity is cot²Ф - csc²Ф = -1 ⇒ last answer

Step-by-step explanation:

* For any point (x , y) lies on the terminal side of the angle Ф

in standard position

* x = cosФ and y = sinФ

- If Ф in the first quadrant, then x , y are positive

∴ All trigonometry functions are positive

- If Ф in the second quadrant, then x is negative , y is positive

∴ sinФ only is positive

- If Ф in the third quadrant, then x is negative , y is negative

∴ tanФ only is positive

- If Ф in the fourth quadrant, then x is positive , y is negative

∴ cosФ only is positive

* Lets solve the problems

∵ Ф = 3π/4 ⇒ (135°)

∴ It lies on the second quadrant

∴ x is negative and y is positive

* Lets revise the reciprocal of sinФ, cosФ and tanФ

- cscФ = 1/sinФ

- secФ = 1/cosФ

- cotФ = 1/tanФ

∵ secФ = -37/12

∴ cosФ = -12/37

∵ π/2 < Ф < π

∴ Ф lies on the second quadrant

∴ cotФ is negative values

∵ tan²Ф = sec²Ф - 1

∵ secФ = -37/12

∴ tan²Ф = (-37/12)² - 1 = 1225/144 ⇒ take√ for both sides

∴ tanФ = ± 35/12

∵ cotФ = ± 12/35

∵ cotФ is negative value

∴ cotФ = -12/35

* In the standard position of the angle Ф the terminal

of it lies on the unit circle O

- By using Pythagorean theorem

∵ x² + y² = 1

∵ x = cosФ and y = sinФ

∴ cos²Ф + sin²Ф = 1 ⇒ (1)

∴ cos²Ф = 1 - sin²Ф

∴ sin²Ф = 1 - cos²Ф

* Divide (1) by cos²Ф

∴ cos²Ф/cos²Ф + sin²Ф/cos²Ф = 1/cos²Ф

* Remember sin²Ф/cos²Ф = tan²Ф and 1/cos²Ф = sec²Ф

∴ 1 + tan²Ф = sec²Ф ⇒ (2) ⇒ subtract 1 from both sides

∴ tan²Ф = sec²Ф - 1 ⇒ subtract sec²Ф from both sides

∴ tan²Ф - sec²Ф = -1

* Divide (1) by sin²Ф

∴ cos²Ф/sin²Ф + sin²Ф/si²Ф = 1/sin²Ф

* Remember cos²Ф/sin²Ф = cot²Ф and 1/sin²Ф = csc²Ф

∴ cot²Ф + 1 = csc²Ф ⇒ (3) ⇒ subtract 1 from both sides

∴ cot²Ф = csc²Ф - 1 ⇒ subtract csc²Ф from both sides

∴ cot²Ф - csc²Ф = -1

* The right identity is cot²Ф - csc²Ф = -1

3 0

3 years ago