The length of rectangular mosaic flag is 710 feet and width is 470 feet
Step-by-step explanation:
Let l be the length of the flag
and
w be the width
Then according to given statement
l = w+240
Perimeter = 2360 feet
The formula for perimeter is given by:

Putting values
![2360 = 2[w+240+w]\\\frac{2360}{2} = \frac{2[w+240+w]}{2}\\1180 = 2w+240\\1180-240 = 2w+240-240\\940 = 2w](https://tex.z-dn.net/?f=2360%20%3D%202%5Bw%2B240%2Bw%5D%5C%5C%5Cfrac%7B2360%7D%7B2%7D%20%3D%20%5Cfrac%7B2%5Bw%2B240%2Bw%5D%7D%7B2%7D%5C%5C1180%20%3D%202w%2B240%5C%5C1180-240%20%3D%202w%2B240-240%5C%5C940%20%3D%202w)
Dividing both sides by 2

The width is 470 feet
Now,

Hence,
The length of rectangular mosaic flag is 710 feet and width is 470 feet
Keywords: Perimeter, dimensions
Learn more about perimeter at:
#LearnwithBrainly
E because 8*8=64 so 8/49*8/49 = 64/49
Answer:
31465 ways
Step-by-step explanation:
Given data
Let us apply the combination formula
nCr = n! / r! * (n - r)!
n= 31
r= 4
substitute
= 31!/4!(31-4)!
= 31!/4!(27)!
= 31*30*29*28*27!/ 4!(27)!
= 31*30*29*28/4!
=31*30*29*28/4*3*2*1
=755160/24
=31465 ways
Hence there are 31465 possible ways to rank it
<h3>Answer:</h3>
301.6 cubic meters
<h3>Step-by-step explanation:</h3>
A cylinder is a shape with straight sides with circular or oval cross-sections. We know that the cylinder in the question must be a circular cylinder due to its radius description.
Volume Formula
A circular cylinder has a volume of
. In this equation, V is the volume, r is the radius, and h is the height. The question tells us that r=4m and h=6m. So, we can plug these values into the formula.
Solving for Volume
To solve plug the values into the formula and rewrite the equation.
Next, apply the exponents.
Then, multiply the constants.
Finally, multiply the remaining terms. Remember to use the pi button on the calculator and not an estimation to get a more exact value.
Make sure your answer is rounded to the correct digit. This means that the volume must be 301.6 cubic meters.
Answer:
Step-by-step explanation:
You need to use synthetic division to do all of these. The thing to remember with these is that when you start off with a certain degree polyomial, what you get on the bottom line after the division is called the depressed polynomial (NOT because it has to math all summer!) because it is a degree lesser than what you started.
a. 3I 1 3 -34 48
I'm going to do this one in its entirety so you get the idea of how to do it, then you'll be able to do it on your own.
First step is to bring down the first number after the bold line, 1.
3I 1 3 -34 48
_____________
1
then multiply it by the 3 and put it up under the 3. Add those together:
3I 1 3 -34 48
3
----------------------------
1 6
Now I'm going to multiply the 6 by the 3 after the bold line and add:
3I 1 3 -34 48
3 18
_________________
1 6 -16
Same process, I'm going to multiply the -16 by the 3 after the bold line and add:
3I 1 3 -34 48
3 18 -48
___________________
1 6 -16 0
That last zero tells me that x-3 is a factor of that polynomial, AND that the depressed polynomial is one degree lesser and those numbers there under that line represent the leading coefficients of the depressed polynomial:

Factoring that depressed polynomial will give you the remaining zeros. Because this was originally a third degree polynomial, there are 3 zeros as solutions. Factoring that depressed polynomial gives you the remaining zeros of x = -8 and x = 2
I am assuming that since you are doing synthetic division that you have already learned the quadratic formula. You could use that or just "regular" factoring would do the trick on all of them.
Do the remaining problems like that one; all of them come out to a 0 as the last "number" under the line.
You got this!