set h=0 and solve for <span>t
</span>So: 0 = 32t - 16^2
<span>32t−16<span>t2</span>=0</span><span>16t(2−t)=0</span><span><span>t=2
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You said d = r t
Divide each side by ' t ' : d / t = r
First let us find the length of JN
JN =JK +KN
JN = 82+105 = 187
JN=187..............(1)
UC= JN -( JH +HU+CN)
We are given :
JH= 22, HU = 96 and CN = 51
plugging all the values we get
UC = 187-( 22+96+51)
UC =187 -169
UC = 18
Answer is UC =18 ( option B)
Answer:
1) 3( 2) - 1 = 6 - 1 = 5
2) 2(-1) - 3+4(-1) = -2 -7 = -9
3) 4^2-6(4)=9 = 16-24=9, = -8=9
Answer: y coordinate is 6
Step-by-step explanation:
6=1/2(3)(h)
If you solve for H then
h=4
So, add 4 to the line y=2
y=2+4
2+4= 6
Hence, the possible y coordinate of point C is 6
Hope this helped!
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