Question

What is the approximate solution of this system of equaltion y=x^2+3x+3 , y=x^2+x+2

Answer 1

Answer:

(B

The given system of equations are:

y=x^2+3x+3y=x

2

+3x+3 (1)

and y=x^2+x+2y=x

2

+x+2 (2)

Subtracting equation (2) from (1), we get

0=2x+10=2x+1

⇒2x=-12x=−1

⇒x={\frac{-1}{2}}x=

2

−1

⇒x=-0.5x=−0.5

Now, substituting the value of x=-0.5 in equation (2), we get

y=0.25-0.5+2y=0.25−0.5+2

⇒y=1.7y=1.7

Thus, the values of x and y are -0.5 and 1.7.

Therefore, the approximate solution of the given system of the equation is (-0.5, 1.7).

Hence, option (B) is correct.