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xz_007 [3.2K]
3 years ago
7

Please help! :):):);)

Mathematics
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

So 60% of this unknown number is 28

Let this unknown number be n

60/100 × n = 28

0.60 × n = 28

n = 28/0.6

n = 46.7

To the nearest wholw number is 47

So there are 47 votes in total

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Can someone answer this math question please???
Lapatulllka [165]

Answer:

TOO MUCH!!!

Step-by-step explanation:

8 0
3 years ago
309 / 17 equals plz need help
MaRussiya [10]
309/17 equals about 18.176 but it’s a rounded answer/decimal.
8 0
3 years ago
What is f(+3) if f(x) = 5 x
Damm [24]

Answer:

f(x) = 5x \\ f(3) = 5(3) =  \boxed{15}

<h3><u>f(</u><u>3</u><u>) =15</u> is the right answer.</h3>
4 0
2 years ago
The LB Company has long manufactured a light bulb with an average life of 5400 hours. Company researchers have recently develope
elena55 [62]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the average life of light bulbs.

As per given , we have

Null hypothesis : H_0 : \mu =5400

Alternative hypothesis : H_a : \mu >5400

Since H_a is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Formula for Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

\sigma=population standard deviation

For n=95,\ \overline{x}=5483\ \&\ \sigma=500, we have

z=\dfrac{5483-5400}{\dfrac{500}{\sqrt{95}}}=1.61796786124\approx1.6180

Using z-value table , Critical one-tailed test value for 0.06 significance level :

z_{0.06}=1.5548

 Decision : Since critical z value (1.5548) < test statistic (1.6180), so we reject the null hypothesis .

[We reject the null hypothesis when critical value is less than the test statistic value .]

Conclusion : We have enough evidence at 0.06 significance level to support the claim that the new filament yields a longer bulb life

8 0
3 years ago
Factor this expression
Natasha_Volkova [10]

Answer:

6(3x−4y)

Step-by-step explanation:

6 0
2 years ago
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