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Kitty [74]
3 years ago
14

The sample mean foot length of a simple random sample of 25 third-graders is 22.5 cm. The standard error of the mean is 0.8 cm.

Which one of the following is a correct interpretation for the standard error of the mean? A.The typical distance between each individual foot length in the sample and the sample mean foot length is approximately 0.8 cm. B.The typical distance between one sample mean foot length and another sample mean foot length is 0.8 cm. C.The typical distance between each individual foot length in the population and the true mean foot length is approximately 0.8 cm. D.The typical distance between means of samples of size 25 and the population mean foot length is approximately 0.8 cm E.The typical distance between each individual foot length in the sample and the true mean foot length is approximately 0.8 cm.
Mathematics
1 answer:
aev [14]3 years ago
8 0

Answer:

Step-by-step explanation:

The standard error is used to determine the difference between the sample mean of the data and the true population mean.

Standard error = population standard deviation/square root of the number of samples

Given that the sample mean foot length of a simple random sample of 25 third-graders is 22.5 cm and the standard error of the mean is 0.8 cm, the correct interpretation for the standard error of the mean is

D. The typical distance between means of samples of size 25 and the population mean foot length is approximately 0.8 cm

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I need help, the options are: Corresponding Angles, Vertical Angles, Alternate interior angles, linear pair, alternate exterior
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Answer:

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✔️<2 and <6 => alternate exterior angles

✔️<2 and <4 => corresponding angles

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Step-by-step explanation:

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<1 and <3 are vertical angles.

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<2 and <6 both lie outside the straight lines cut across by the transversal, and they also lie in the side of the transversal alternating each other

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3 years ago
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Answer:

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The general solution values  

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Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

                              2cosx =\sqrt{3}

Dividing '2' on both sides, we get

                             cos x =\frac{\sqrt{3} }{2}

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<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

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Answer:

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