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Dmitry [639]
3 years ago
14

138.4divided by16 show works it possible to show your work

Mathematics
1 answer:
Lorico [155]3 years ago
4 0
Ok done. Thank to me :>

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Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
Pls say hard very hard​
Simora [160]

(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.

(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?

On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:

50 ≤ score ≤ 60   ==>   50-60

60 < score ≤ 70   ==>   60-70

70 < score ≤ 80   ==>   70-80

80 < score ≤ 90   ==>   80-90

90 < score ≤ 100   ==>   90-100

Then a student who scored a 60 should be added to the 50-60 category.

8 0
3 years ago
Your little cousin will have a big animal-themed birthday party and you will help with the goody bags. Each bag will have a penc
Bas_tet [7]

Using the least common factor, it is found that:

  • a) 60 packages should be bought.
  • b) There will be 5 filled goody bags.

<h3>Least Common Factor:</h3>
  • The sizes of the packages are: 10, 6, 15 and 12.
  • To fill each bag and have no left-overs, the number of packages is the <u>least common factor</u> of these amounts.
  • The least common factor is found factoring the numbers into prime factors.

Item a:

10 - 6 - 15 - 12|2

5 - 3 - 15 - 6|2

5 - 3 - 15 - 3|3

5 - 1 - 5 - 1|5

1 - 1 - 1 - 1

Hence, lcf(10,6,15,2) = 2 x 2 x 3 x 5 = 60.

60 packages should be bought.

Item b:

Goody bags are in packages of 12, hence:

60/12 = 5.

There will be 5 filled goody bags.

To learn more about the least common factor, you can take a look at brainly.com/question/24873870

6 0
2 years ago
Will give brainliest please help <br><br>4b + 7b +5 <br><br>i need help simplifying.​
vitfil [10]

Answer:

11b+5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Pre algebra help ( will give brainliest ) sorry if it's hard to see
valentinak56 [21]
It would have changed by 1/3 is ur answer
4 0
4 years ago
Read 2 more answers
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