Answer:
Either, (9+√69)/6 or (9-√69)/6
Step wise:
3x²-9x+1=0-------------------(i)
comparing equation onw with (ax²+bx+c=0), we get,
a=3, b=-9, c=1
now,
using Quadratic Formula,
(-b±√b²-4ac)/2a=x
{-(-9)±√(-9)²-4.3.1}/2.3=x
(9±√81-12)/6=x
(9±√69)/6=x
Taking +(ve) sign Taking -(ve) sign
(9+√69)/6=0 (9-√69)/6=0
∴(9+√69)/6=0 ∴(9-√69)/6=0
[∵They cannot be further solved]
Let b = blue marbles
y = yellow marbles
Sum = b+y
The <span>chance of a blue marble being drawn first is:
b / (b+y) = 0.55
</span>The <span>chance of a blue marble being drawn first then a yellow next is:
</span>b / (b+y) * <span>y / (b+y-1) = 0.37</span>
This can be solve easily by using a theorem of Bayes
0.37/0.55 = .67 or 67%
Step-by-step explanation:
sin theta = opp / hyp
sin theta × hyp = opp
sin60 × 30 = opp
.866 × 30 = opp
25.98° = opp
*Theta is the 0 with a line through it
Answer:
x = -2 and y = 2
Step-by-step explanation:
The given equations are :
-5x-2y=6 ...(1)
3x+6y=6 ...(2)
Multiply equation (1) by 3. SO,
-15x-6y=18 ...(3)
Adding equation (2) and (3).
3x+6y-15x-6y = 6+18
-12x = 24
x = -2
Put the value of x in equation (1).
-5(-2)-2y=6
10-2y=6
4=2y
y = 2
So, the value of x is -2 and y is 2.
The ages of people on the camp bus are listed. 10, 15, 14, 8, 18, 11, 12, 12, 10, 10, 17, 16 What is the mode of the ages? A. 10
Ghella [55]
A. 10 because it occurs the most times in the sequence and the other numbers don't have as many as the the number 10. 10 appears 3 times
