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3 years ago

13

Determine the range for the function y = (x - 3 )^2 + 4.

1 answer:

Aleksandr [31]3 years ago

7 0

Answer:

<h3>Solutions are x=2 and x=−2 . At these points the function has vertical asymptotes. To address the range, let's first transform...</h3>

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Answer:

d the negatives canceled each other out making it positive

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Jenna can buy 5 golf balls at Golf Central for $9.20 or 4 golf balls at Strictly Golf for $7.60. Jenna wants to buy 20 golf ball

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$1.20

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2 years ago

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Consider m = y2 - y1/ x2 - x1 . Which x1 and x2-values would determine that the line is vertical? Justify your answer

Y_Kistochka [10]

Answer:

$x_2=x_1$

Step-by-step explanation:

We were given the slope formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

This line is vertical if the denominator is zero.

That is when $x_2-x-1=0$

This implies that;

$x_2=x_1$

Justification;

When $x_2=x_1$ , then, the line passes through;

$(x_1,y_1)$ and $(x_1,y_2)$

The slope now become

$m=\frac{y_2-y_1}{x_1-x_1}=\frac{y_2-y_1}{0}$

The equation of the line is

$y-y_1=\frac{y_2-y_1}{0}(x-x_1)$

This implies that;

$0(y-y_1)=(y_2-y_1)(x-x_1)$

$0=(y_2-y_1)(x-x_1)$

$\frac{0}{y_2-y_1}=(x-x_1)$

$0=(x-x_1)$

$x=x_1$ ... This is the equation of a vertical line.

3 0

3 years ago

Given the following formula, with A = 27 and t = 3, solve for r. <br> A=p(1+rt)

Nookie1986 [14]

Answer:

<h2>A. $r=\frac{27-p}{3p}$ </h2>

Step-by-step explanation:

The given formula is

$A=p(1+rt)$

Where $A=27$ and $t=3$

To solve for $r$ , first we need to move $p$

$\frac{A}{p}=1+rt$

Then, we move the term 1

$\frac{A}{p}-1=rt$

Finally, we move the factor $t$

$\frac{\frac{A}{p}-1 }{t} =r$

Replacing given values, we have

$\frac{\frac{27}{p}-1 }{3} =r\\r=\frac{\frac{27-p}{p} }{3} \\r=\frac{27-p}{3p}$

Thereofre, the right answer is A.

7 0

3 years ago