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4 years ago

Oak Grove and Salem are 78 km from

Mathematics

1 answer:

Sophie [7]4 years ago

5 0

Answer:

690 km will take it.for good condition

Step-by-step explanation:

mark me BRAINLIEST

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PLEASE HELP ME: ASAP

VashaNatasha [74]

Ok so

Corresponding sides and angles are a pair of matching angles or sides that are in the same spot in two different shapes.

It would basically be a ratio (7:14)

My best help would be this

If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides. This proves that the ratio of areas of two similar triangles is proportional to the squares of the corresponding sides of both the triangles.

I really hope this helps, dont have a lot of time today to answer a lot of questions so have a great day and lmk if this helps!

4 0

3 years ago

Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)

Lisa [10]

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

$x^2-2x + y^2 - 6y = 26$

Typically, the equation of a circle would be in the form $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center and $r$ is the radius.

To get the given equation $x^2-2x + y^2 - 6y = 26$ into this form, we must complete the square for both x and y.

1) Complete the square for x

Let's take a look at this part of the equation:

$x^2-2x$

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

$x^2-2x+1$

Great! Now, let's add this to our original equation:

$x^2-2x+1+y^2-6y = 26$

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

$x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27$

Complete the square:

$(x-1)^2+y^2-6y = 27$

2) Complete the square for y

Let's take a look at this part of the equation $(x-1)^2+y^2-6y = 27$ :

$y^2-6y$

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

$y^2-6y+9$

Great! Now, back to our original equation:

$(x-1)^2+y^2-6y+9= 27$

Remember to add 9 on the other side as well:

$(x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36$

Complete the square:

$(x-1)^2+(y-3)^2= 36$

3) Determine the center and the radius

$(x-1)^2+(y-3)^2= 36$

$(x-h)^2+(y-k)^2=r^2$

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

3 0

3 years ago

Read 2 more answers

Draw and compare models of 3/4 of a pizza pie and 6/8 of a same-size pie.

Reptile [31]

Have a good day look down to see the answers its in paint.

4 0

3 years ago

Which is the graph of a quadratic equation that has a positive discriminant?

masya89 [10]

If the discriminant is positive,that means that there are roots that are real and therefore, when y=0, the roots are there and for the quadratic to meet it has to go down (or up if in ax²+bx+c a is negative). If the discriminant is 0, that means that since the x value of the vertex is -b/2a and if you have
x= $\frac{-b+- \sqrt{b^2 -4ac} }{2a} 
$ and b^2-4ac=0, we're left with 0 and we are therefore left with -b/2a as the vertex and the vertex being the x intercept. If the discriminant is negative, that means that there is no y intercept and the vertex therefore has to be over y=0

6 0

4 years ago

How do I solve this?

Ilya [14]

A=bh/2

A=2/3ft*3/5ft/2

A=2/3×5/5*3/5×3/3/2

A=10/15*9/15/2

A=90÷15/2

A=6ft^2

8 0

3 years ago

Read 2 more answers