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Pavel [41]
3 years ago
14

Is there any other euations that can apply to it

Mathematics
1 answer:
shutvik [7]3 years ago
5 0
I don’t understand apply to what?
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Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
Use the number 8,6, and 2 and one operation to write an expression that includes an exponent and has a value of 8. Use each numb
podryga [215]

6 + 2^1 = 8 is the expression that includes an exponent and has a value of 8

<em><u>Solution:</u></em>

Given that, Use the number 8, 6, and 2 and one operation to write an expression that includes an exponent and has a value of 8

We have to use each number only once

Given numbers are 8, 6, 2

Our expression should include exponent and the result should be 8

Among 6 and 2 we can use 2 for exponent

Raise 2 to power of 1

<em><u>The expression becomes:</u></em>

6 + 2^1 = 8

Here we have used one operation, that is addition

Verifying the expression

6 + 2^1 = 6 + 2 = 8

Thus the required expression is found

8 0
3 years ago
Which are partcial products<br> for 34 x 28
Novosadov [1.4K]

Answer:

952

Step-by-step explanation:

34 = (30 + 4)

28 = (20 + 8)

34 x 28 = (30 + 4) x (20 + 8)

34 x 28 = 30 x 20 + 30 x 8 + 4 x 20 + 4 x 8

34 x 28 = 600 + 240 + 80 + 32

34 x 28 = 952

952 = 952

3 0
3 years ago
write an equation in point-slope form for the line through the given point with the given slope (10,-9);m=-2​
fgiga [73]

Answer:

The answer is

<h2>y + 9 =  - 2(x - 10)</h2>

Step-by-step explanation:

To find the equation of a line given a point and slope we use the formula

<h3>y - y1 = m(x - x1)</h3>

where

m is the slope

( x1 , y1) is the point

From the question

Slope / m = - 2

The point is ( 10, - 9)

Substitute the values into the above formula

That's the final answer is

<h3>y + 9 =  - 2(x - 10)</h3>

Hope this helps you

5 0
3 years ago
Maria and her family drove 885 miles on their summer vacation. The first 8 on the left in this number has a ____ of 800
Rudiy27
The first 8 on the left in this. umber has a VALUE of 800. :)
5 0
3 years ago
Read 2 more answers
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