Question

How many solutions does this linear system have?

Answer 1

Answer:

Option 2 - One solution: (2.5, 0)                  

Step-by-step explanation:

Given : Two linear equation -

Equation 1 - $y = 2x - 5$

Equation 2 - $-8x - 4y = -20$

To find : How many solutions does this linear system have?

Solution :

We solve the given equations,

Substitute the value of y from equation 1 in equation 2

$-8x - 4y = -20$

$-8x - 4(2x-5) = -20$

$-8x - 8x+20 = -20$

$-16x=-40$

$x=\frac{40}{16}$

$x=2.5$

Now, put value of x in equation 1

$y = 2x - 5$

$y = 2(2.5) - 5$

$y = 5 - 5$

$y = 0$

There is one solution (x,y) = (2.5, 0)

Option 2 is correct.

Answer 2

The solution is (2.5,0)....