To check if distances can be a triangle add the smaller two distances together. If the sum is larger (not equal to) than the longest distance then it is a possible side. For example, 2,2,4 or 1,2,5cannot be a triangle, 2,3, 4 can be a triangle because 2+3 is greater than 4.
Answer:
2xy(x+5)(4x−1)
Step-by-step explanation:
1 Find the Greatest Common Factor (GCF).
GCF = 2xy
2 Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
2xy (8x^3y + 38x^2y/2xy + −10xy/2xy)
3 Simplify each term in parentheses.
2xy(4x^2 +19x−5)
4 Split the second term in 4x^2+19x-5 into two terms.
2xy(4x^2 +20x−x−5)
5 Factor out common terms in the first two terms, then in the last two terms.
2xy(4x(x+5)−(x+5))
6 Factor out the common term x+5.
2xy(x+5)(4x−1)
Answer: 99.51%
Step-by-step explanation:
Given : A survey found that women's heights are normally distributed.
Population mean : 
Standard deviation: 
Minimum height = 4ft. 9 in.=
Maximum height = 6ft. 2 in.=
Let x be the random variable that represent the women's height.
z-score : 
For x=57, we have
For x=74, we have
Now, by using the standard normal distribution table, we have
The probability of women meeting the height requirement :-
Hence, the percentage of women meeting the height requirement = 99.51%
If you would like to write 7/8 as a decimal, you can do this using the following steps:
7/8 = (125*7)/1000 = 875/1000 = 0.875 = .875
The correct result would be b. .875.
