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2 years ago

10

A Donut Shop serves plain and chocolates donuts at a ratio of 5 to 3. Based on this ratio, how many chocolate donuts will be ser

ved if there are a total of 120 donuts served?

1 answer:

jolli1 [7]2 years ago

3 0

Answer:

75

Step-by-step explanation:

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a drink recipe calls for lemon juice and apple juice. the equation below represents the proportional relationship between the cu

GREYUIT [131]

Answer: ima newbie

Step-by-step explanation:

Always include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their own. Show all the calculation if it is a numerical question.

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2 years ago

Round the following numbers to the nearest 10<br> a) 83<br> b) 127<br> c) 245

dolphi86 [110]

I believe the answer is-
a) 80
b) 130
c) 250

5 0

3 years ago

A camera has a listed price of $587.98 before tax. If the sales tax rate is 8.5%, find the total cost of the camera with sales t

ikadub [295]

Answer:

$637.95

Step-by-step explanation:

convert 8.5% to a decimal by dividing by 100:

8.5÷100= 0.085

then multiply.

587.98×(0.085)=49.97

now add.

587.98+49.97=<u>637.95</u>

6 0

3 years ago

Can sides of a triangle have lengths 1, 13, and 14 ???

victus00 [196]

Answer: Yes it can!

Step-by-step explanation:

This is called a scalene triangle, where all 3 sides are different lengths.

5 0

3 years ago

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

7 0

3 years ago