Answer:
Research what kind of computer you want.
Explanation:
I don't know exactly what you are asking here but when doing research you have got to know what you want like how much ram you want, how much storage you want, what brand of computer you want, what core processor you want, and what graphics card you want. You also have to decide if you want a laptop or a full sized desk top computer.
I think it would be crop !
Answer:
Explanation:
How to meet people in real life
1. We can meet people if you go to your friend's party, is a great opportunity to meet friends from your friends.
2. We must go to events, in this case, if you like to read books, go to reading events.
3. We can use public transportation if you see someone reading your favorite book is the best opportunity.
How to meet people online
1. We can meet people in social media, but there are a lot of fake accounts, take care.
2. There are special platforms to meet people or to find love.
3. We could meet people on educational websites or apps, for example, if we want to learn Spanish, we can meet Spanish people.
Answer:
The following code is in C++.
#include <iostream>
using namespace std;
int main() {
int a[10],sum=0;//declaring an array and initialized variable sum with value 0.
cout<<"Enter the numbers"<<endl;
for(int i=0;i<10;i++)
{
cin>>a[i]; //taking input of 10 integers.
}
for(int i=0;i<10;i++)
{
sum=sum+a[i];//finding the sum..
}
cout<<"The sum is : "<<sum<<endl<<"The numbers entered are "<<endl;
for(int i=0;i<10;i++)
{
cout<<a[i]<<" ";//displaying the elements.
}
return 0;
}
Output:-
Enter the numbers
1 2 3 4 5 6 7 8 9 10
The sum is : 55
The numbers entered are
1 2 3 4 5 6 7 8 9 10
Explanation:
I have taken an array of size 10 so that no more than 10 integers could fit in it.After that taking the input from the user prompting 10 integers using the for loop.After that finding the sum.Then printing the sum and the numbers entered.
Answer:
Here it is
Explanation:
#include <iostream>
using namespace std;
int main()
{
int a, b;
cin >> a >> b;
int nr_digits1 = 0, nr_digits2 = 0;
int sum1 = 0, sum2 = 0;
int max_digit1 = 0, max_digit2 = 0;
while (a > 1)
{
int digit = a % 10;
nr_digits1 += 1;
sum1 += digit;
if (digit > max_digit1)
{
max_digit1 = digit;
}
a /= 10;
}
while (b > 1)
{
int digit = b % 10;
nr_digits2 += 1;
sum2 += digit;
if (digit > max_digit2)
{
max_digit2 = digit;
}
b /= 10;
}
cout << "For a: \n" << " No. of digits: " << nr_digits1 << "\n";
cout << " Sum of digits: " << sum1 << "\n";
cout << " Max digit: " << max_digit1 << "\n";
cout << "\n";
cout << "For b: \n" << " No. of digits: " << nr_digits2 << "\n";
cout << " Sum of digits: " << sum2 << "\n";
cout << " Max digit: " << max_digit2 << "\n";
return 0;
}
