Simple: Keep your camera protected from the rain
Here are some tips for photographing during rainy day: 1) Use image stabilization or tripod.
2) Choose a larger aperture.
3) Change the object on which you focus.
4) Have a well-defined center of interest.
5) Review all images.
6) Use exposure compensation.
Answer: I need more info to answer this question
Explanation:
The answer is <span>ESRI. It </span>offers a complete graphic information system software solution for computer-generated maps that stores all its data in your oracle 10g database. It stands for Environmental Systems Research Institute. Esri's<span> GIS mapping software is the most powerful mapping and spatial data analytics technology available.</span>
Is it multiple choice or an essay question? If its an essay question I would say Living alone, being able to rent YOU'RE own home, and probably being able to decorate it the way you want.
Answer:
#include <iostream>
using namespace std;
int * reverse(int a[],int n)//function to reverse the array.
{
int i;
for(i=0;i<n/2;i++)
{
int temp=a[i];
a[i]=a[n-i-1];
a[n-i-1]=temp;
}
return a;//return pointer to the array.
}
int main() {
int array[50],* arr,N;//declaring three variables.
cin>>N;//taking input of size..
if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..
return 0;
for(int i=0;i<N;i++)
{
cin>>array[i];//prompting array elements..
}
arr=reverse(array,N);//function call.
for(int i=0;i<N;i++)
cout<<arr[i]<<endl;//printing reversed array..
cout<<endl;
return 0;
}
Output:-
5
4 5 6 7 8
8
7
6
5
4
Explanation:
I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.
