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3 years ago

How can you tell if a function is quadratic?

1 answer:

3 0

There are several ways, but the general format follows f(x) = ax2 + bx + c f(x) = ax² + bx + c, where A, B, and C are non-zero numbers. Another way of finding a quadratic equation is examining the graph of it, you'll notice a "U" shape called a parabola, which come in many shapes but they all retain a "U"-like curve.

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PLS HELP MEEEEE And please SHOW YOUR WORK

vfiekz [6]

$- 13.8 = \frac{u}{5} - 1.3$

$- 13.8 + 1.3 = \frac{u}{5}$

$- 12.5 = \frac{u}{5}$

$- 12.5 \times 5 = u$

$- 62.5 = u$

4 0

3 years ago

(8n+1)(6n-3) please solve in quadratic formula

cestrela7 [59]

Use the distributive property.

$(8n+1)(6n-3)=(8n)(6n)+(8n)(-3)+(1)(6n)+(1)(-3)\\\\=48n^2-24n+6n-3=48n^2-18n-3$

5 0

3 years ago

Suppose that a department contains 10 men and 12 women. How many ways are there to form a committee with six members if it must

Readme [11.4K]

Answer:

The number of ways is 26,400 ways

Step-by-step explanation:

Given;

total number of men, M = 10

total number of women, W = 12

number of committees to be formed = 6

If there must be equal gender, then it must consist of 3 men and 3 women.

$The \ number \ of \ ways = 10C_3 \times 12C_3\\\\The \ number \ of \ ways =\frac{10!}{3!7!} \times \frac{12!}{3!9!} \\\\T he \ number \ of \ ways = 120 \times 220 = 26,400 \ ways$

Therefore, the number of ways is 26,400 ways

8 0

2 years ago

Find the slope of the line passing through each of the following pairs of points and draw the graph of the line.

tiny-mole [99]

Answer:

The slope is 1/2

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A backyard pool has a concrete walkway around it that is 3 feet wide on all sides. The total area of the pool and the walkway is

Gnoma [55]

Answer:

<h2>29.4 length and 21.4 width.</h2>

Step-by-step explanation:

To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that W is the width and L the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this: $A_{total} = (L+6)(W+6)$ .

In addition, we know that the total area is 970 and the length is 8 ft longer than the width ( $L=W+8$ ). So:

$A_{total} = (L+6)(W+6)\\970 = (W+8+6)(W+6)\\970=W^{2}+20W+84\\W^{2}+20W-886=0$

With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions: $W_{1}=21.4$ and $W_{2}=-41.4$

Therefore, the width is 21.4 ft, because the negative number cannot represent distances.

Using the relation between length and width:

$L=W+8\\L=21.4+8=29.4$

Therefore, the dimensions of the pool are 29.4 length and 21.4 width.

7 0

3 years ago