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3 years ago

How can you tell if a function is quadratic?

1 answer:

3 0

There are several ways, but the general format follows f(x) = ax2 + bx + c f(x) = ax² + bx + c, where A, B, and C are non-zero numbers. Another way of finding a quadratic equation is examining the graph of it, you'll notice a "U" shape called a parabola, which come in many shapes but they all retain a "U"-like curve.

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What is the simplified value of the expression below? 1/3 divided by 2/3

lidiya [134]

Answer:

6/3

Step-by-step explanation:

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3 years ago

Which expression is equivalent to 3(5 + 6)?

Ulleksa [173]

Answer:

3(5+6)=33 15+18=33

Step-by-step explanation:

good luck

4 0

3 years ago

What is the value of x? A 6x - 3 3x + 6 B. 5x 3 4 05 02

choli [55]

Unclear plssss make it clear

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3 years ago

At the end of the ride up a steep hill, Ken was at an elevation of 1600 meters above where he started. He figured out that he an

Lostsunrise [7]

Answer:

Step-by-step explanation:

first place)

in first place you must Know by definition that a joule is defined as the amount of work done by a constant force in a meter of length

and it is 1 J = 1 N ×m = 1 kg ×m/s² ×m= 1 Kg×m²/s²

now you can calculate the time done by ken and his bicycle

1000000 = 52kg×(1600)²/s² = 1000000= 133120000/s²⇒1000000s² = 133120000⇒s²= 133120000/1000000⇒ s² =133,12⇒s =√133,12 = 11,5 ≅12

12 s is the time that ken with his bicycle ride up to the mountain

second )

having the time you can calculate the work done by ken individually

52kg×(1600)²/(12)² =133120000/ (12)² = 924444,4 and this is the work done by ken

Now you must substract the work done by ken and his bicycle from the work done by ken individually in order to know the work of the bicycle

1000000 joules -924444,4 joules = 75555,6 joules

Having this amount, you can calculate the mass of the bicycle

and it is 1 J = 1 N ×m = 1 kg ×m/s² ×m= 1 Kg×m²/s²

75555,6 = kg *(1600) ²/(12)²⇒ 75555,6 =17777,7kg⇒ Kg = 75555,6/17777,7 = 4,25 kg

the mass of the ken's bicycle is 4,25 kg

3 0

3 years ago

Let s be the part of the sphere x2 + y2 + z2 = 100 that lies above the plane z = 6. let s have constant density k. (a) find the

astra-53 [7]

center of mass = (0, 0, 96/13) exactly (0, 0, 7.3846) approximately. The object described is a spherical cap for a sphere with a radius of 10. Since the sphere is centered at the origin, the center of mass will have X and Y coordinates of 0 and we only need to find the Z coordinate. The formula for the geometric centroid of a spherical cap is: z = 3(2R - h)^2 / 4(3R - h) where z = distance from the center of the sphere R = radius of sphere h = distance from base of spherical cap to top of spherical cap And for a spherical cap of uniform density, the geometric centroid is also known as the center of mass. Since the sphere has a radius of 10 and is cut by the plane z=6, the value h will be 10-6 = 4. So substitute the known values into the formula: z = 3(2R - h)^2 / 4(3R - h) z = 3(2*10 - 4)^2 / 4(3*10 - 4) z = 3(20 - 4)^2 / 4(30 - 4) z = 3(16)^2 / 4(26) z = 3(256) / 104 z = 768/104 z = 96/13 z ~= 7.384615385

6 0

3 years ago