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3 years ago

8

In a survey of 23 college students it was found that 17 were taking an english class 10 were taking a math class and 8 were taki

ng both english and math. how many students were talking a math only class?
a. 6
b. 14
c. 2
d. 4

1 answer:

Sliva [168]3 years ago

6 0

Answer:

2

Step-by-step explanation:

out of 10 that were taking math 8 of them were also taking english. 10-8=2

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3 years ago

The perimeter of a rectangle is 42 inches, and its area is 110 square inches. find the length and width of the rectangle.

lorasvet [3.4K]

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You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:

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(p) ÷ 2 = (2w + 2l) ÷ 2
$2's$ $cancel$ $out$
$\frac{p}{2} = w + l$

Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself).
$\frac{p}{2} - l = w + l - l$
$l's$ $cancel$ $out$
p/2 - l = w

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You replace w with the equation above p/2 - l = w
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Multiply out the L.
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Plug in all your numbers a = 110 and p = 42
$110 = \frac{42}{2}l - l^{2}$
$110 = 21l - l^{2$

Move everything to the left side so $l^{2}$ would be positive (makes the equation easier when $l^{2}$ is positive).
$l^{2} - 21l + 110 = 0$

Factor.
$(l -10)(l-11) = 0$

Make each parenthesis set equal to 0.
$l-11=0$ $l-10=0$

Add.
$l = 11$ $l = 10$

By doing this you solve for both the width and length so the answer is:
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3 years ago