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STatiana [176]
3 years ago
10

A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different five-card hands are pos

sible?
A) 260 hands
B) 2,598,960 hands
C) 24,380 hands
D) 311,875,200 hands
Mathematics
2 answers:
jok3333 [9.3K]3 years ago
7 0
I think the answer is B
AlexFokin [52]3 years ago
7 0

Answer:

B) 2,598,960 hands

Step-by-step explanation:

This is a combination problem. So we can use the next formula:

C(n,k)=nCk=\frac{n!}{k!(n-k)!}

Where:

n=Number\hspace{3}of\hspace{3}elements=52\\k=Number\hspace{3}of\hspace{3}combinations= 5

So:

52C_5=\frac{52!}{5!(47!)}=2598960\hspace{3}hands

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pickupchik [31]

Answer:

35 bricks for $25.90

35 bricks for $25.90

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Step-by-step explanation:

Cost per brick = number of bricks / price of bricks

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230 / $170.20 = $1.35

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Based on these calculations, the bricks that have the same cost per brick are :

35 bricks for $25.90

35 bricks for $25.90

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7 0
2 years ago
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Answer:Marti is not correct as a rhombus is not a kite . there are various difference between a rhombus and a kite . all sides of a rhombus are equal whereas all sides of a kite are not equal

Step-by-step explanation:

7 0
2 years ago
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Mademuasel [1]

Answer:

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Step-by-step explanation:

To find the inverse of a function replace the positions of x and y. Then isolate y.

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x = 4y

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5 0
3 years ago
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Katyanochek1 [597]
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Answer:

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Step-by-step explanation:

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