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3 years ago

If 6 chocolate chip cookies cost $2.40. What will 9 chocolate chip cookies cost?

Mathematics

2 answers:

Yuri [45]3 years ago

8 0

$3.60 sksodjehbwjsidifjhejwkaoz

Bumek [7]3 years ago

5 0

6 chocolates cookies = 2.40

1 chocolate cookie = 0.4

9 chocolates cookies = 3.60

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according to a recent survey, in 2000, 64% of households had one or more pets.Throughout the next decade, this decreased by appr

ehidna [41]

Answer:

Year 2034

Step-by-step explanation:

In 2000, 64% had one or more pets

Since decreasing at 1% per year, we can say:

In 2001, 63%

In 2002, 62%

In 2003, 61%

In 2004, 60%

And so on

To go to 30% from 60% in 2004, we would need to decrease 60 - 30 = 30%, and that will occur after 30 more years. So that would be the year

2004 + 30 = 2034

So, year 2034

3 0

2 years ago

How can I construct a truth table for ~(p ^ q)?

bekas [8.4K]

Attached below is a step by step process of arriving at the answer.

3 0

3 years ago

What is the solution to this system of equations? 4x + 5y = 7 3x – 2y = –12

oksano4ka [1.4K]

Answer:

x = -2 and y = 3

Step-by-step explanation:

It is given that,

4x + 5y = 7 -----(1)

3x – 2y = –12 ----(2)

To find the value of x and y

eq(1) * 3 ⇒

12x + 15y = 21 ----(3)

eq(2) * 4 ⇒

12x - 8y = -48 ---(4)

eq(3) - eq(4) ⇒

12x + 15y = 21 ----(3)

12x - 8y = -48 ---(4)

0 + 23y = 69

y = 69/23 = 3

Substitute the value of y in eq(1)

4x + 5y = 7 ----(1)

4x + 5*3 = 7

4x = 7 - 15 = -8

x = -8/4 = -2

Therefore x = -2 and y = 3

5 0

2 years ago

carmen bought 15 case of juice for a party. she bought 3 cases of bottled water for every 5 case of juice she bought for the par

Crazy boy [7]

Nine I believe, because fifth teen divided by five equals three
three times three equals nine.

3 0

3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0

3 years ago